{"id":84,"date":"2023-07-26T09:16:40","date_gmt":"2023-07-26T09:16:40","guid":{"rendered":"https:\/\/chemuza.org\/tr\/lewis-yapisi-n3\/"},"modified":"2023-07-26T09:16:40","modified_gmt":"2023-07-26T09:16:40","slug":"lewis-yapisi-n3","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/lewis-yapisi-n3\/","title":{"rendered":"N3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/Structure-de-Lewis-n3.jpg\" alt=\"N3-Lewis yap\u0131s\u0131\" class=\"wp-image-601\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">Lewis yap\u0131s\u0131 N3- (azid iyonu) \u00fc\u00e7 nitrojen (N) atomuna sahiptir. Her nitrojen (N) atomu aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. D\u0131\u015ftaki iki nitrojen atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. D\u0131\u015f nitrojen atomlar\u0131ndan (N) birinde resmi y\u00fck -1&#8217;dir.<\/mark><\/em><\/strong><\/p>\n<p> Yukar\u0131daki Lewis yap\u0131s\u0131 N3- (azid iyonu) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/compound\/Azide-ion\" target=\"_blank\" rel=\"noopener\">N3- iyonunun<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi N3 iyonunun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>N3 Lewis yap\u0131s\u0131n\u0131n \u00e7izimindeki ad\u0131mlar<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: N3 iyonundaki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> N3 iyonundaki (azid iyonu) <a href=\"https:\/\/www.chemeurope.com\/en\/encyclopedia\/Valence_electron.html\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektronlar\u0131n\u0131n<\/a> toplam say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle tek bir nitrojen <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">atomunda<\/a> bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak nitrojenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>N3 iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-4.jpg\" alt=\"\" class=\"wp-image-84\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Azot<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">15. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/7\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 <strong>5&#8217;tir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-4.jpg\" alt=\"\" class=\"wp-image-85\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>N3 iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong> = 3 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 negatif y\u00fck nedeniyle eklenen ekstra 1 elektron = <strong>5(3) + 1 = 16<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl N3&#8217;t\u00fcr. Her \u00fc\u00e7 atom da ayn\u0131d\u0131r, dolay\u0131s\u0131yla atomlardan herhangi birini merkez atom olarak se\u00e7ebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"56\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-1.webp\" alt=\"N3-ad\u0131m 1\" class=\"wp-image-602\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi N3 molek\u00fcl\u00fcnde <a href=\"https:\/\/en.wikipedia.org\/wiki\/Electron_pair\" target=\"_blank\" rel=\"noopener\">elektron \u00e7iftlerini<\/a> \u00fc\u00e7 nitrojen (N) atomu aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"59\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-2.webp\" alt=\"N3-ad\u0131m 2\" class=\"wp-image-603\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, N3 molek\u00fcl\u00fcnde \u00fc\u00e7 nitrojen (N) atomunun <a href=\"https:\/\/chem.fsu.edu\/chemlab\/chm1045\/bonding.html\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada N3 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n yaln\u0131zca nitrojen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici nitrojen atomlar\u0131 bir <a href=\"https:\/\/en.wikipedia.org\/wiki\/Octet_rule\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"263\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-3.webp\" alt=\"N3-ad\u0131m 3\" class=\"wp-image-604\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda N3- iyonunda bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> N3- iyonunun toplam <strong>16 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki diyagramda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi nitrojen (N) atomunun kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi nitrojen (N) atomunun stabilitesini kontrol etmek i\u00e7in onun bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Ne yaz\u0131k ki merkezi nitrojen atomu burada bir oktet olu\u015fturmuyor. Azotun sadece 4 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"254\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-4.webp\" alt=\"N3-ad\u0131m 4\" class=\"wp-image-605\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi, bu nitrojen atomunu stabil hale getirmek i\u00e7in, d\u0131\u015ftaki nitrojen atomunun elektron \u00e7iftini, merkezi nitrojen atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"108\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-5.webp\" alt=\"N3-ad\u0131m 5\" class=\"wp-image-606\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ancak bir \u00e7ift elektronu hareket ettirdikten sonra merkezi nitrojen atomu, yaln\u0131zca 6 elektrona sahip oldu\u011fundan hala bir oktet olu\u015fturmuyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"241\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-6.webp\" alt=\"N3-ad\u0131m 6\" class=\"wp-image-607\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yine di\u011fer nitrojen atomundan fazladan bir \u00e7ift elektronu hareket ettirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"105\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-7.webp\" alt=\"N3-ad\u0131m 7\" class=\"wp-image-608\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra merkezi nitrojen atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"235\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-8.webp\" alt=\"N3-ad\u0131m 8\" class=\"wp-image-609\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde merkezi nitrojen atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Ve b\u00f6ylece bu nitrojen atomu kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi N3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k N3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/www.chem.ucalgary.ca\/courses\/353\/Carey5th\/Ch01\/ch1-3-2.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k N3 molek\u00fcl\u00fcnde bulunan t\u00fcm nitrojen (N) atomlar\u0131n\u0131n formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde N3 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"234\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-9.webp\" alt=\"N3-ad\u0131m 9\" class=\"wp-image-610\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Merkezi nitrojen atomu (N) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 5 (\u00e7\u00fcnk\u00fc nitrojen 15. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Harici nitrojen (N) atomlar\u0131 i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 5 (\u00e7\u00fcnk\u00fc nitrojen 15. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> N (merkezi)<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 5<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>+1<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> N (d\u0131\u015f)<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 5<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki resmi y\u00fck hesaplamalar\u0131ndan merkezi nitrojen (N) atomunun <strong>-1<\/strong> , d\u0131\u015ftaki nitrojen atomlar\u0131n\u0131n ise <strong>-1<\/strong> y\u00fck\u00fcne sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> O halde bu y\u00fckleri N3 molek\u00fcl\u00fcn\u00fcn ilgili atomlar\u0131nda tutal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"89\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-10.webp\" alt=\"N3-ad\u0131m 10\" class=\"wp-image-611\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki diyagramdaki <strong>+1<\/strong> ve <strong>-1<\/strong> y\u00fckleri iptal edilir ve yukar\u0131daki diyagramda yaln\u0131zca <strong>-1<\/strong> y\u00fck\u00fc kal\u0131r, bu da N3 molek\u00fcl\u00fcnde resmi <strong>-1<\/strong> y\u00fck\u00fcyle sonu\u00e7lan\u0131r.<\/p>\n<p> N3 molek\u00fcl\u00fcndeki bu genel <strong>-1<\/strong> y\u00fck\u00fc a\u015fa\u011f\u0131daki resimde g\u00f6sterilmektedir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"99\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/n3-etape-11.webp\" alt=\"N3-ad\u0131m 11\" class=\"wp-image-612\" srcset=\"\" sizes=\"\"><\/figure>\n<p> N3 iyonunun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak size N3 iyonunun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131n\u0131 verecektir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-n3.jpg\" alt=\"N3-'\u00fcn Lewis yap\u0131s\u0131\" class=\"wp-image-613\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bh3-lewis-yapisi\/\">Lewis Yap\u0131s\u0131 BH3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-c2h6-lewis\/\">Lewis yap\u0131s\u0131 C2H6<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/cocl2-lewis-yapisi\/\">Lewis yap\u0131s\u0131 COCl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-brf5-yapisi\/\">BrF5 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-ncl3un-yapisi\/\">Lewis Yap\u0131s\u0131 NCl3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/chcl3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 CHCl3<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 N3- (azid iyonu) \u00fc\u00e7 nitrojen (N) atomuna sahiptir. Her nitrojen (N) atomu aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. D\u0131\u015ftaki iki nitrojen atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. D\u0131\u015f nitrojen atomlar\u0131ndan (N) birinde resmi y\u00fck -1&#8217;dir. Yukar\u0131daki Lewis yap\u0131s\u0131 N3- (azid iyonu) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, &#8230; <a title=\"N3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-n3\/\" aria-label=\"More on N3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>N3- 6 ad\u0131mda Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-n3\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"N3- 6 ad\u0131mda Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 N3- (azid iyonu) \u00fc\u00e7 nitrojen (N) atomuna sahiptir. Her nitrojen (N) atomu aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. D\u0131\u015ftaki iki nitrojen atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. D\u0131\u015f nitrojen atomlar\u0131ndan (N) birinde resmi y\u00fck -1&#8217;dir. Yukar\u0131daki Lewis yap\u0131s\u0131 N3- (azid iyonu) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, ... 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Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 N3- (azid iyonu) \u00fc\u00e7 nitrojen (N) atomuna sahiptir. Her nitrojen (N) atomu aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. D\u0131\u015ftaki iki nitrojen atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. D\u0131\u015f nitrojen atomlar\u0131ndan (N) birinde resmi y\u00fck -1&#8217;dir. Yukar\u0131daki Lewis yap\u0131s\u0131 N3- (azid iyonu) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, ... 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