{"id":67,"date":"2023-07-26T12:34:22","date_gmt":"2023-07-26T12:34:22","guid":{"rendered":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/"},"modified":"2023-07-26T12:34:22","modified_gmt":"2023-07-26T12:34:22","slug":"scn-yapisi-lewis","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/","title":{"rendered":"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-scn-lewis.jpg\" alt=\"SCN-Lewis yap\u0131s\u0131\" class=\"wp-image-730\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">SCN-Lewis yap\u0131s\u0131n\u0131n merkezinde bir k\u00fck\u00fcrt (S) atomu ve bir nitrojen (N) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon (C) ve k\u00fck\u00fcrt (S) atomlar\u0131 ile karbon (C) ve nitrojen (N) atomlar\u0131 aras\u0131nda 2 adet \u00e7ift ba\u011f vard\u0131r. Azot (N) atomunun resmi y\u00fck\u00fc -1&#8217;dir.<\/mark><\/em><\/strong><\/p>\n<p> SCN iyonunun (tiyosiyanat iyonu) Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, o zaman benimle kal\u0131n ve <a href=\"https:\/\/en.wikipedia.org\/wiki\/Thiocyanate\" target=\"_blank\" rel=\"noopener\">SCN iyonunun<\/a> yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi SCN-ion&#8217;un <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>SCN-Lewis yap\u0131s\u0131n\u0131 \u00e7izme ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: SCN molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> SCN iyonundaki (tiyosiyanat iyonu) <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektronlar\u0131n\u0131n<\/a> toplam say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">k\u00fck\u00fcrt atomunda<\/a> , karbon atomunda ve nitrojen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak k\u00fck\u00fcrt, karbon ve nitrojenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>SCN iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 K\u00fck\u00fcrt atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-3.jpg\" alt=\"\" class=\"wp-image-66\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">K\u00fck\u00fcrt<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/16\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle k\u00fck\u00fcrtteki de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"273\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-3.jpg\" alt=\"\" class=\"wp-image-67\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi k\u00fck\u00fcrt atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/1.jpg\" alt=\"\" class=\"wp-image-25\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Karbon<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">14. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/6\/carbon\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 <strong>4&#8217;t\u00fcr<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2.jpg\" alt=\"\" class=\"wp-image-26\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-4.jpg\" alt=\"\" class=\"wp-image-84\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Azot<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">15. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/education.jlab.org\/itselemental\/ele007.html\" target=\"_blank\" rel=\"noopener\"><sup>[3]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 <strong>5&#8217;tir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-4.jpg\" alt=\"\" class=\"wp-image-85\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>SCN iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 k\u00fck\u00fcrt atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 negatif y\u00fck nedeniyle eklenen 1 ekstra elektron = <strong>6 + 4 + 5 + 1 = 16<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl SCN&#8217;dir ve bir k\u00fck\u00fcrt atomu (S), bir karbon atomu (C) ve bir nitrojen atomu (N) i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda k\u00fck\u00fcrt atomunun (S), karbon atomunun (C) ve nitrojen atomunun (N) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> K\u00fck\u00fcrt atomu (S), karbon atomu (C) ve nitrojen atomunun (N) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak, <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">karbon atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada karbon (C) atomu merkez atom, k\u00fck\u00fcrt (S) atomu ve nitrojen (N) atomu ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"66\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-1.webp\" alt=\"SCN-ad\u0131m 1\" class=\"wp-image-731\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi SCN molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> k\u00fck\u00fcrt atomu (S), karbon atomu (C) ve nitrojen atomu (N) aras\u0131na yerle\u015ftirmeniz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"57\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-2.webp\" alt=\"SCN-a\u015fama 2\" class=\"wp-image-732\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bir SCN molek\u00fcl\u00fcnde k\u00fck\u00fcrt atomunun (S), karbon atomunun (C) ve nitrojen atomunun (N) birbirine <a href=\"https:\/\/www.britannica.com\/science\/chemical-bonding\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada SCN molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n k\u00fck\u00fcrt atomu ve nitrojen atomu oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici k\u00fck\u00fcrt ve nitrojen atomlar\u0131 bir oktet olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"263\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-3.webp\" alt=\"SCN-ad\u0131m 3\" class=\"wp-image-733\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda SCN iyonunda bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> SCN iyonunun toplam <strong>16 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki diyagramda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi karbon atomunun (C) kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi karbon (C) atomunun stabilitesini kontrol etmek i\u00e7in oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Maalesef karbon atomu burada bir oktet olu\u015fturmuyor. Karbonun yaln\u0131zca 4 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"254\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-4.webp\" alt=\"SCN-ad\u0131m 4\" class=\"wp-image-734\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi, bu karbon atomunu kararl\u0131 hale getirmek i\u00e7in, d\u0131\u015ftaki k\u00fck\u00fcrt atomunun elektron \u00e7iftini, karbon atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"105\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-5.webp\" alt=\"SCN-ad\u0131m 5\" class=\"wp-image-735\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ancak bir \u00e7ift elektronu hareket ettirdikten sonra karbon atomu yaln\u0131zca 6 elektrona sahip oldu\u011fundan hala bir oktet olu\u015fturmuyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"240\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-6.webp\" alt=\"SCN-ad\u0131m 6\" class=\"wp-image-736\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yine nitrojen atomundan fazladan bir \u00e7ift elektronu hareket ettirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"105\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-7.webp\" alt=\"SCN-ad\u0131m 7\" class=\"wp-image-737\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra merkezi karbon atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"240\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-8.webp\" alt=\"SCN-ad\u0131m 8\" class=\"wp-image-738\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde karbon atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Ve bu nedenle karbon atomu kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi SCN&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k SCN molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/s10.lite.msu.edu\/res\/msu\/botonl\/b_online\/library\/newton\/Chy251_253\/Lectures\/Formal_Charge\/FormalChargeFS.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k SCN molek\u00fcl\u00fcnde bulunan k\u00fck\u00fcrt (S), karbon (C) ve nitrojen (N) atomlar\u0131n\u0131n formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde SCN molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"235\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-9.webp\" alt=\"SCN-ad\u0131m 9\" class=\"wp-image-739\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>K\u00fck\u00fcrt (S) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc k\u00fck\u00fcrt 16. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4<\/p>\n<p> <strong>Karbon atomu (C) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 4 (\u00e7\u00fcnk\u00fc karbon 14. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Azot atomu (N) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 5 (\u00e7\u00fcnk\u00fc nitrojen 15. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> S<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> VS<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> OLUMSUZ<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 5<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan nitrojen (N) atomunun <strong>-1<\/strong> , di\u011fer atomlar\u0131n ise <strong>0<\/strong> y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> \u00d6yleyse bu y\u00fckleri SCN molek\u00fcl\u00fcn\u00fcn ilgili atomlar\u0131nda tutal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"90\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-10.webp\" alt=\"SCN-ad\u0131m 10\" class=\"wp-image-740\" srcset=\"\" sizes=\"\"><\/figure>\n<p> SCN molek\u00fcl\u00fcndeki bu genel <strong>-1<\/strong> y\u00fck a\u015fa\u011f\u0131daki resimde g\u00f6sterilmektedir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"104\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/scn-etape-11.webp\" alt=\"SCN-ad\u0131m 11\" class=\"wp-image-741\" srcset=\"\" sizes=\"\"><\/figure>\n<p> SCN iyonunun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"https:\/\/www.britannica.com\/science\/single-bond\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak SCN-iyonunun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"226\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/Structure-Lewis-de-SCN.jpg\" alt=\"SCN'nin Lewis yap\u0131s\u0131-\" class=\"wp-image-742\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/cl2-lewis-yapisi\/\">Lewis yap\u0131s\u0131 Cl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-hf-yapisi\/\">HF Lewis Yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-scl2-yapisi\/\">Lewis yap\u0131s\u0131 SCl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-pf5-yapisi\/\">Lewis yap\u0131s\u0131 PF5<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/h2so4-lewis-yapisi\/\">Lewis yap\u0131s\u0131 H2SO4<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/c2h5oh-etanol-lewis-yapisi\/\">Etanol\u00fcn Lewis yap\u0131s\u0131 (C2H5OH)<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. SCN-Lewis yap\u0131s\u0131n\u0131n merkezinde bir k\u00fck\u00fcrt (S) atomu ve bir nitrojen (N) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon (C) ve k\u00fck\u00fcrt (S) atomlar\u0131 ile karbon (C) ve nitrojen (N) atomlar\u0131 aras\u0131nda 2 adet \u00e7ift ba\u011f vard\u0131r. Azot (N) atomunun resmi y\u00fck\u00fc -1&#8217;dir. SCN &#8230; <a title=\"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\" aria-label=\"More on 6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. SCN-Lewis yap\u0131s\u0131n\u0131n merkezinde bir k\u00fck\u00fcrt (S) atomu ve bir nitrojen (N) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon (C) ve k\u00fck\u00fcrt (S) atomlar\u0131 ile karbon (C) ve nitrojen (N) atomlar\u0131 aras\u0131nda 2 adet \u00e7ift ba\u011f vard\u0131r. Azot (N) atomunun resmi y\u00fck\u00fc -1&#8217;dir. SCN ... Devam\u0131n\u0131 oku\" \/>\n<meta property=\"og:url\" content=\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\" \/>\n<meta property=\"og:site_name\" content=\"Chemuza\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-26T12:34:22+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-scn-lewis.jpg\" \/>\n<meta name=\"author\" content=\"Edit\u00f6r ekibi\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Edit\u00f6r ekibi\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\"},\"author\":{\"name\":\"Edit\u00f6r ekibi\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\"},\"headline\":\"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\",\"datePublished\":\"2023-07-26T12:34:22+00:00\",\"dateModified\":\"2023-07-26T12:34:22+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\"},\"wordCount\":1266,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"articleSection\":[\"Lewis yap\u0131s\u0131\"],\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\",\"url\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\",\"name\":\"6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#website\"},\"datePublished\":\"2023-07-26T12:34:22+00:00\",\"dateModified\":\"2023-07-26T12:34:22+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Ev\",\"item\":\"https:\/\/chemuza.org\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/chemuza.org\/tr\/#website\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"name\":\"Chemuza\",\"description\":\"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!\",\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/chemuza.org\/tr\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"tr\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\",\"name\":\"Chemuza\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"contentUrl\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"width\":387,\"height\":70,\"caption\":\"Chemuza\"},\"image\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\",\"name\":\"Edit\u00f6r ekibi\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"caption\":\"Edit\u00f6r ekibi\"},\"sameAs\":[\"http:\/\/chemuza.org\/tr\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/","og_locale":"tr_TR","og_type":"article","og_title":"6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza","og_description":"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. SCN-Lewis yap\u0131s\u0131n\u0131n merkezinde bir k\u00fck\u00fcrt (S) atomu ve bir nitrojen (N) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon (C) ve k\u00fck\u00fcrt (S) atomlar\u0131 ile karbon (C) ve nitrojen (N) atomlar\u0131 aras\u0131nda 2 adet \u00e7ift ba\u011f vard\u0131r. Azot (N) atomunun resmi y\u00fck\u00fc -1&#8217;dir. SCN ... Devam\u0131n\u0131 oku","og_url":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/","og_site_name":"Chemuza","article_published_time":"2023-07-26T12:34:22+00:00","og_image":[{"url":"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-scn-lewis.jpg"}],"author":"Edit\u00f6r ekibi","twitter_card":"summary_large_image","twitter_misc":{"Yazan:":"Edit\u00f6r ekibi","Tahmini okuma s\u00fcresi":"6 dakika"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#article","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/"},"author":{"name":"Edit\u00f6r ekibi","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e"},"headline":"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)","datePublished":"2023-07-26T12:34:22+00:00","dateModified":"2023-07-26T12:34:22+00:00","mainEntityOfPage":{"@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/"},"wordCount":1266,"commentCount":0,"publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"articleSection":["Lewis yap\u0131s\u0131"],"inLanguage":"tr","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/","url":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/","name":"6 ad\u0131mda SCN-Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle birlikte) - Chemuza","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/#website"},"datePublished":"2023-07-26T12:34:22+00:00","dateModified":"2023-07-26T12:34:22+00:00","breadcrumb":{"@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#breadcrumb"},"inLanguage":"tr","potentialAction":[{"@type":"ReadAction","target":["https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/chemuza.org\/tr\/scn-yapisi-lewis\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Ev","item":"https:\/\/chemuza.org\/tr\/"},{"@type":"ListItem","position":2,"name":"6 ad\u0131mda scn-lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)"}]},{"@type":"WebSite","@id":"https:\/\/chemuza.org\/tr\/#website","url":"https:\/\/chemuza.org\/tr\/","name":"Chemuza","description":"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!","publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/chemuza.org\/tr\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"tr"},{"@type":"Organization","@id":"https:\/\/chemuza.org\/tr\/#organization","name":"Chemuza","url":"https:\/\/chemuza.org\/tr\/","logo":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/","url":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","contentUrl":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","width":387,"height":70,"caption":"Chemuza"},"image":{"@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e","name":"Edit\u00f6r ekibi","image":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","caption":"Edit\u00f6r ekibi"},"sameAs":["http:\/\/chemuza.org\/tr"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/67"}],"collection":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/comments?post=67"}],"version-history":[{"count":0,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/67\/revisions"}],"wp:attachment":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/media?parent=67"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/categories?post=67"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/tags?post=67"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}