{"id":59,"date":"2023-07-26T14:09:25","date_gmt":"2023-07-26T14:09:25","guid":{"rendered":"https:\/\/chemuza.org\/tr\/asetik-asit-ch3coohun-lewis-yapisi\/"},"modified":"2023-07-26T14:09:25","modified_gmt":"2023-07-26T14:09:25","slug":"asetik-asit-ch3coohun-lewis-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/asetik-asit-ch3coohun-lewis-yapisi\/","title":{"rendered":"Ch3cooh (asetik asit) 6 ad\u0131mda lewis yap\u0131s\u0131"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-ch3cooh-lewis.jpg\" alt=\"Lewis yap\u0131s\u0131 CH3COOH (asetik asit)\" class=\"wp-image-1000\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">CH3COOH (asetik asit) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir COOH grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbona ba\u011fl\u0131 \u00fc\u00e7 CH ba\u011f\u0131 ve bir COOH fonksiyonel grubu vard\u0131r. \u0130ki oksijen (O) atomunda 2 yaln\u0131z \u00e7ift vard\u0131r.<\/mark><\/em><\/strong><\/p>\n<p> CH3COOH&#8217;un Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/compound\/Acetic-Acid\" target=\"_blank\" rel=\"noopener\">CH3COOH&#8217;un<\/a> (asetik asit) Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi CH3COOH&#8217;nin (asetik asit) <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>CH3COOH Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: CH3COOH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> Bir CH3COOH <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/energyeducation.ca\/encyclopedia\/Valence_and_core_electrons\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektronu<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">karbon atomunda<\/a> , hidrojen atomunda ve oksijen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">size periyodik tabloyu<\/a> kullanarak karbon, hidrojen ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>CH3COOH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/1.jpg\" alt=\"\" class=\"wp-image-25\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Karbon<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">14. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/6\/carbon\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 <strong>4&#8217;t\u00fcr<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2.jpg\" alt=\"\" class=\"wp-image-26\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Hidrojen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3.jpg\" alt=\"\" class=\"wp-image-27\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Hidrojen periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">1. grup<\/a> elementidir. <a href=\"https:\/\/education.jlab.org\/itselemental\/ele001.html\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle hidrojende bulunan de\u011ferlik elektronu <strong>1&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"177\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4.jpg\" alt=\"\" class=\"wp-image-28\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi hidrojen atomunda yaln\u0131zca bir de\u011ferlik elektronunun bulundu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/8.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[3]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>CH3COOH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 2 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 4 hidrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>4(2) + 1(4) + 6(2) = 24<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> <strong>(Unutmay\u0131n:<\/strong> e\u011fer verilen molek\u00fclde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">hidrojen<\/a> varsa, daima hidrojeni d\u0131\u015far\u0131ya koyun.)<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl CH3COOH&#8217;dur ve karbon (C) atomlar\u0131, hidrojen (H) atomlar\u0131 ve oksijen (O) atomlar\u0131n\u0131 i\u00e7erir.<\/p>\n<p> Yani kurala g\u00f6re hidrojeni d\u0131\u015far\u0131da tutmal\u0131y\u0131z. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Art\u0131k yukar\u0131daki periyodik tabloda karbon atomunun (C) ve oksijen atomunun (O) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Karbon (C) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak, <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">karbon atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada karbon (C) atomlar\u0131 merkez atom, oksijen (O) atomu ise d\u0131\u015f atomdur. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"141\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-1.webp\" alt=\"CH3COOH ad\u0131m 1\" class=\"wp-image-1001\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ba\u015fka bir \u015fekilde, karbon atomunun \u00fc\u00e7 hidrojen atomu ve bir COOH grubu taraf\u0131ndan \u00e7evrelendi\u011fini de g\u00f6rebilirsiniz.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi CH3COOH molek\u00fcl\u00fcnde <a href=\"https:\/\/doi.org\/10.1038\/s41570-018-0052-4\" target=\"_blank\" rel=\"noopener\">elektron \u00e7iftlerini<\/a> karbon (C), oksijen (O) ve hidrojen (H) atomlar\u0131 aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"141\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-2.webp\" alt=\"CH3COOH ad\u0131m 2\" class=\"wp-image-1002\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bu atomlar\u0131n bir CH3COOH molek\u00fcl\u00fcnde birbirine <a href=\"https:\/\/www.lamar.edu\/arts-sciences\/_files\/documents\/chemistry-biochemistry\/dorris\/chapter8.pdf\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada CH3COOH molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n hidrojen atomlar\u0131 ve oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu hidrojen ve oksijen atomlar\u0131 s\u0131ras\u0131yla bir <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ikili<\/a> ve <a href=\"https:\/\/en.wikipedia.org\/wiki\/Octet_rule\" target=\"_blank\" rel=\"noopener\">bir oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"305\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-3.webp\" alt=\"CH3COOH ad\u0131m 3\" class=\"wp-image-1003\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda CH3COOH molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> CH3COOH molek\u00fcl\u00fcn\u00fcn toplam <strong>24 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki CH3COOH diyagram\u0131nda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi karbon atomlar\u0131n\u0131n (C) kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi karbon (C) atomlar\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in bunlar\u0131n bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Maalesef karbon atomlar\u0131ndan biri burada bir oktet olu\u015fturmuyor. Sadece 6 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"317\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-4.webp\" alt=\"CH3COOH ad\u0131m 4\" class=\"wp-image-1004\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi, bu karbon atomunu kararl\u0131 hale getirmek i\u00e7in, d\u0131\u015ftaki oksijen atomunun elektron \u00e7iftini, karbon atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"164\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-5.webp\" alt=\"CH3COOH ad\u0131m 5\" class=\"wp-image-1005\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra karbon atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"278\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-6.webp\" alt=\"CH3COOH ad\u0131m 6\" class=\"wp-image-1006\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde karbon atomunun 8 elektrona sahip olmas\u0131 nedeniyle bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> \u015eimdi CH3COOH&#8217;un Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k CH3COOH&#8217;un Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/www.chem.ucalgary.ca\/courses\/353\/Carey5th\/Ch01\/ch1-3-2.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k CH3COOH molek\u00fcl\u00fcnde bulunan karbon (C), hidrojen (H) ve oksijen (O) atomlar\u0131n\u0131n formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde CH3COOH molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"294\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3cooh-etape-7.webp\" alt=\"CH3COOH ad\u0131m 7\" class=\"wp-image-1007\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Karbon atomu (C) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 4 (\u00e7\u00fcnk\u00fc karbon 14. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Hidrojen atomu (H) i\u00e7in:<\/strong><br \/> De\u011ferlik elektronu = 1 (\u00e7\u00fcnk\u00fc hidrojen grup 1&#8217;dedir)<br \/> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Oksijen atomu (O) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> VS<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> H<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 1<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Ah<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan karbon (C), hidrojen (H) ve oksijen (O) atomlar\u0131n\u0131n <strong>&#8220;s\u0131f\u0131r&#8221;<\/strong> formal y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, CH3COOH&#8217;un yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve CH3COOH&#8217;nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> CH3COOH&#8217;un yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak CH3COOH&#8217;un a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"287\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-ch3cooh.jpg\" alt=\"CH3COOH'un (asetik asit) Lewis yap\u0131s\u0131\" class=\"wp-image-1008\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bro3-lewisin-yapisi\/\">BrO3-Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-cbr4-yapisi\/\">Lewis yap\u0131s\u0131 CBr4<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/locn-lewis-yapisi\/\">OCN-Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-icl4\/\">ICl4-Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sif4un-yapisi\/\">Lewis yap\u0131s\u0131 SiF4<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-ch3f-lewis\/\">CH3F Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3COOH (asetik asit) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir COOH grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbona ba\u011fl\u0131 \u00fc\u00e7 CH ba\u011f\u0131 ve bir COOH fonksiyonel grubu vard\u0131r. \u0130ki oksijen (O) atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. CH3COOH&#8217;un Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden &#8230; <a title=\"Ch3cooh (asetik asit) 6 ad\u0131mda lewis yap\u0131s\u0131\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/asetik-asit-ch3coohun-lewis-yapisi\/\" aria-label=\"More on Ch3cooh (asetik asit) 6 ad\u0131mda lewis yap\u0131s\u0131\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 ad\u0131mda CH3COOH (asetik asit) Lewis yap\u0131s\u0131 - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/asetik-asit-ch3coohun-lewis-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 ad\u0131mda CH3COOH (asetik asit) Lewis yap\u0131s\u0131 - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? 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