{"id":47,"date":"2023-07-26T16:24:52","date_gmt":"2023-07-26T16:24:52","guid":{"rendered":"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/"},"modified":"2023-07-26T16:24:52","modified_gmt":"2023-07-26T16:24:52","slug":"lewis-yapisi-yok","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/","title":{"rendered":"No 5 ad\u0131mda lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-de-structure-Lewis-1.jpg\" alt=\"HAYIR Lewis yap\u0131s\u0131\" class=\"wp-image-376\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">NO Lewis yap\u0131s\u0131nda bir nitrojen (N) atomu ve aralar\u0131nda \u00e7ift ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Oksijen (O) atomunun 2 ortaks\u0131z \u00e7ifti, nitrojen (N) atomunun ise 1 ortaks\u0131z \u00e7ifti ve 1 e\u015flenmemi\u015f elektronu vard\u0131r.<\/mark><\/em><\/strong><\/p>\n<p> NO&#8217;nun Lewis yap\u0131s\u0131na (Nitrik Oksit veya Nitrik Oksit) ili\u015fkin yukar\u0131daki resimden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, o zaman benimle kal\u0131n ve <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/compound\/Nitric-oxide\" target=\"_blank\" rel=\"noopener\">NO&#8217;nun<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izimine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi NO&#8217;nun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>NO Lewis Yap\u0131s\u0131n\u0131 \u00c7izme Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: NO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">NO (nitrik oksit) molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/energyeducation.ca\/encyclopedia\/Valence_and_core_electrons\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle tek bir nitrojen <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">atomunda<\/a> ve bir oksijen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak nitrojenin ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>NO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-4.jpg\" alt=\"\" class=\"wp-image-84\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Azot<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">15. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/education.jlab.org\/itselemental\/ele007.html\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 <strong>5&#8217;tir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-4.jpg\" alt=\"\" class=\"wp-image-85\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/8.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>NO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>5 + 6 = 11<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> Burada verilen molek\u00fcl NO&#8217;dur (azot monoksit). Yaln\u0131zca iki atomu vard\u0131r, dolay\u0131s\u0131yla bunlardan herhangi birini merkez atom olarak se\u00e7ebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"59\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-1-1.webp\" alt=\"HAYIR ad\u0131m 1\" class=\"wp-image-377\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Azot atomunun merkezi bir atom oldu\u011funu varsayal\u0131m.<br \/> (En az elektronegatif atomu merkez atom olarak d\u00fc\u015f\u00fcnmelisiniz).<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi NO molek\u00fcl\u00fcnde <a href=\"https:\/\/doi.org\/10.1038\/s41570-018-0052-4\" target=\"_blank\" rel=\"noopener\">elektron \u00e7iftlerini<\/a> nitrojen (N) atomu ile oksijen (O) atomu aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"59\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-2-1.webp\" alt=\"HAYIR ad\u0131m 2\" class=\"wp-image-378\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, nitrojen (N) atomunun ve oksijen (O) atomunun bir NO molek\u00fcl\u00fcnde <a href=\"https:\/\/www.lamar.edu\/arts-sciences\/_files\/documents\/chemistry-biochemistry\/dorris\/chapter8.pdf\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f atomlar\u0131 kararl\u0131 hale getirin. Kalan de\u011ferlik elektron \u00e7iftini merkez atomun \u00fczerine yerle\u015ftirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda harici atomun stabilitesini kontrol etmeniz gerekir.<\/p>\n<p> NO molek\u00fcl\u00fcn\u00fcn \u00e7iziminde nitrojen atomunun merkez atom oldu\u011funu varsayd\u0131k. Oksijen bu nedenle d\u0131\u015f atomdur.<\/p>\n<p> Yani oksijen atomunu kararl\u0131 hale getirmeniz gerekiyor.<\/p>\n<p> A\u015fa\u011f\u0131daki resimde oksijen atomunun bir oktet olu\u015fturdu\u011funu ve bu nedenle kararl\u0131 oldu\u011funu g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"245\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-3-1.webp\" alt=\"HAYIR ad\u0131m 3\" class=\"wp-image-379\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda NO molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> NO molek\u00fcl\u00fcn\u00fcn toplam <strong>11 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>8 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>11 \u2013 8 = 3<\/strong> .<\/p>\n<p> NO molek\u00fcl\u00fcn\u00fcn yukar\u0131daki diyagram\u0131nda bu <strong>3<\/strong> elektronu (yani 1 elektron \u00e7ifti ve 1 e\u015flenmemi\u015f elektron) nitrojen atomuna yerle\u015ftirmeniz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"228\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-4-1.webp\" alt=\"HAYIR ad\u0131m 4\" class=\"wp-image-380\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda nitrojen (N) atomunun kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Azot (N) atomunun stabilitesini kontrol etmek i\u00e7in <a href=\"https:\/\/en.wikipedia.org\/wiki\/Octet_rule\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Ne yaz\u0131k ki nitrojen atomu burada bir oktet olu\u015fturmuyor. Azotun sadece 5 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"262\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-5-1.webp\" alt=\"HAYIR ad\u0131m 5\" class=\"wp-image-381\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bu nitrojen atomunu stabil hale getirmek i\u00e7in oksijen atomunun elektron \u00e7iftini hareket ettirmeniz gerekir, b\u00f6ylece nitrojen atomu daha stabil hale gelebilir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"121\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-6-1.webp\" alt=\"HAYIR ad\u0131m 6\" class=\"wp-image-382\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra nitrojen atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 7 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"246\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/pas-detape-7-1.webp\" alt=\"HAYIR ad\u0131m 7\" class=\"wp-image-383\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Azotun bir oktet olu\u015fturmad\u0131\u011f\u0131n\u0131 g\u00f6rebilirsiniz (\u00e7\u00fcnk\u00fc 7 elektronu vard\u0131r). \u015eimdi elektron \u00e7iftini daha fazla hareket ettirmeye \u00e7al\u0131\u015f\u0131rsan\u0131z 7 + 2 = 9 elektron olacakt\u0131r.<\/p>\n<p> Azot atomunun ise 9 elektron tutma kapasitesi yoktur. Bu nedenle NO&#8217;nun yukar\u0131daki Lewis yap\u0131s\u0131 (nitrojen atomunda 7 elektron bulunan) stabildir.<\/p>\n<p> NO&#8217;nun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"https:\/\/en.wikipedia.org\/wiki\/Single_bond\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak NO&#8217;nun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"199\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-non.jpg\" alt=\"NO'nun Lewis yap\u0131s\u0131\" class=\"wp-image-384\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-n2o-lewis\/\">Lewis yap\u0131s\u0131 N2O<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch3oh-lewis-yapisi\/\">Lewis yap\u0131s\u0131 CH3OH<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-pcl3un-yapisi\/\">PCl3 Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bcl3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 BCl3<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-cf4-yapisi\/\">CF4 Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-xef2-yapisi\/\">Lewis yap\u0131s\u0131 XeF2<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NO Lewis yap\u0131s\u0131nda bir nitrojen (N) atomu ve aralar\u0131nda \u00e7ift ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Oksijen (O) atomunun 2 ortaks\u0131z \u00e7ifti, nitrojen (N) atomunun ise 1 ortaks\u0131z \u00e7ifti ve 1 e\u015flenmemi\u015f elektronu vard\u0131r. NO&#8217;nun Lewis yap\u0131s\u0131na (Nitrik Oksit veya Nitrik Oksit) ili\u015fkin yukar\u0131daki &#8230; <a title=\"No 5 ad\u0131mda lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/\" aria-label=\"More on No 5 ad\u0131mda lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NO 5 Ad\u0131mda Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NO 5 Ad\u0131mda Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NO Lewis yap\u0131s\u0131nda bir nitrojen (N) atomu ve aralar\u0131nda \u00e7ift ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Oksijen (O) atomunun 2 ortaks\u0131z \u00e7ifti, nitrojen (N) atomunun ise 1 ortaks\u0131z \u00e7ifti ve 1 e\u015flenmemi\u015f elektronu vard\u0131r. NO&#8217;nun Lewis yap\u0131s\u0131na (Nitrik Oksit veya Nitrik Oksit) ili\u015fkin yukar\u0131daki ... 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