{"id":31,"date":"2023-07-26T19:33:55","date_gmt":"2023-07-26T19:33:55","guid":{"rendered":"https:\/\/chemuza.org\/tr\/lewis-cs2-yapisi\/"},"modified":"2023-07-26T19:33:55","modified_gmt":"2023-07-26T19:33:55","slug":"lewis-cs2-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/lewis-cs2-yapisi\/","title":{"rendered":"6 ad\u0131mda cs2 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/Structure-de-Lewis-CS2.jpg\" alt=\"Lewis yap\u0131s\u0131 CS2\" class=\"wp-image-342\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">CS2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki k\u00fck\u00fcrt (S) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon atomu (C) ile her k\u00fck\u00fcrt atomu (S) aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. \u0130ki k\u00fck\u00fcrt (S) atomunda 2 yaln\u0131z \u00e7ift vard\u0131r.<\/mark><\/em><\/strong><\/p>\n<p> Yukar\u0131daki CS2 Lewis Yap\u0131s\u0131 (Karbon Dis\u00fclf\u00fcr) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"http:\/\/www.chemspider.com\/Chemical-Structure.6108.html\" target=\"_blank\" rel=\"noopener\">CS2&#8217;nin<\/a> Lewis Yap\u0131s\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u00d6yleyse CS2&#8217;nin <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>CS2 Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: CS2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">CS2 (karbon dis\u00fclfit) molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle k\u00fck\u00fcrt atomunun yan\u0131 s\u0131ra <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">karbon atomunda<\/a> bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">size periyodik tabloyu<\/a> kullanarak hem karbonun hem de k\u00fck\u00fcrt\u00fcn de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>CS2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/1.jpg\" alt=\"\" class=\"wp-image-25\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Karbon<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">14. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/6.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 <strong>4&#8217;t\u00fcr<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2.jpg\" alt=\"\" class=\"wp-image-26\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 K\u00fck\u00fcrt atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-3.jpg\" alt=\"\" class=\"wp-image-66\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">K\u00fck\u00fcrt<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/en.wikipedia.org\/wiki\/Sulfur\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle k\u00fck\u00fcrtte bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"273\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-3.jpg\" alt=\"\" class=\"wp-image-67\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi k\u00fck\u00fcrt atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>CS2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 k\u00fck\u00fcrt atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>4 + 6(2) = 16<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl CS2&#8217;dir (karbon dis\u00fclf\u00fcr) ve karbon (C) atomlar\u0131 ve k\u00fck\u00fcrt (S) atomlar\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda karbon atomunun (C) ve k\u00fck\u00fcrt atomunun (S) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Karbon (C) ve k\u00fck\u00fcrt\u00fcn (S) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak, <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">karbon atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada karbon (C) atomu merkez atom, k\u00fck\u00fcrt (S) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"64\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-1.webp\" alt=\"CS2 ad\u0131m 1\" class=\"wp-image-343\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi CS2 molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> karbon atomu (C) ile k\u00fck\u00fcrt atomlar\u0131 (S) aras\u0131na yerle\u015ftirmeniz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"56\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-2.webp\" alt=\"CS2 a\u015fama 2\" class=\"wp-image-344\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bir CS2 molek\u00fcl\u00fcnde karbon (C) ve k\u00fck\u00fcrt\u00fcn (S) birbirine <a href=\"https:\/\/www.britannica.com\/science\/chemical-bonding\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada CS2 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n k\u00fck\u00fcrt atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici k\u00fck\u00fcrt atomlar\u0131 bir oktet olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"262\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-3.webp\" alt=\"CS2 ad\u0131m 3\" class=\"wp-image-345\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda CS2 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> CS2 molek\u00fcl\u00fcn\u00fcn toplam <strong>16 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki CS2 diyagram\u0131nda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi karbon atomunun (C) kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi karbon (C) atomunun stabilitesini kontrol etmek i\u00e7in oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Maalesef karbon atomu burada bir oktet olu\u015fturmuyor. Karbonun yaln\u0131zca 4 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"255\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-4.webp\" alt=\"CS2 a\u015fama 4\" class=\"wp-image-346\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi, bu karbon atomunu kararl\u0131 hale getirmek i\u00e7in, d\u0131\u015ftaki k\u00fck\u00fcrt atomunun elektron \u00e7iftini, karbon atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"125\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-5.webp\" alt=\"CS2 ad\u0131m 5\" class=\"wp-image-347\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ancak bir \u00e7ift elektronu hareket ettirdikten sonra karbon atomu yaln\u0131zca 6 elektrona sahip oldu\u011fundan hala bir oktet olu\u015fturmuyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"250\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-6.webp\" alt=\"CS2 ad\u0131m 6\" class=\"wp-image-348\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yine di\u011fer k\u00fck\u00fcrt atomundan fazladan bir \u00e7ift elektronu hareket ettirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"105\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-7.webp\" alt=\"CS2 ad\u0131m 7\" class=\"wp-image-349\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra merkezi karbon atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"239\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-8.webp\" alt=\"CS2 ad\u0131m 8\" class=\"wp-image-350\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde karbon atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Ve bu nedenle karbon atomu kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi CS2&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k CS2&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/s10.lite.msu.edu\/res\/msu\/botonl\/b_online\/library\/newton\/Chy251_253\/Lectures\/Formal_Charge\/FormalChargeFS.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131saca art\u0131k CS2 molek\u00fcl\u00fcnde bulunan karbon (C) ve k\u00fck\u00fcrt (S) atomlar\u0131n\u0131n formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde CS2 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"235\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/cs2-etape-9.webp\" alt=\"CS2 ad\u0131m 9\" class=\"wp-image-351\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Karbon atomu (C) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 4 (\u00e7\u00fcnk\u00fc karbon 14. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>K\u00fck\u00fcrt (S) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc k\u00fck\u00fcrt 16. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> VS<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> S<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan, hem <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">karbon (C) atomunun<\/a> hem de <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">k\u00fck\u00fcrt (S) atomunun<\/a> <strong>&#8220;s\u0131f\u0131r&#8221;<\/strong> formal y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, CS2&#8217;nin yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve CS2&#8217;nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> CS2&#8217;nin yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak CS2&#8217;nin a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"194\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-CS2.jpg\" alt=\"CS2'nin Lewis yap\u0131s\u0131\" class=\"wp-image-352\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-ph3-yapisi\/\">PH3 Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/\">HAYIR Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-n2o-lewis\/\">Lewis yap\u0131s\u0131 N2O<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch3oh-lewis-yapisi\/\">Lewis yap\u0131s\u0131 CH3OH<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-pcl3un-yapisi\/\">PCl3 Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bcl3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 BCl3<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CS2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki k\u00fck\u00fcrt (S) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon atomu (C) ile her k\u00fck\u00fcrt atomu (S) aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. \u0130ki k\u00fck\u00fcrt (S) atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. Yukar\u0131daki CS2 Lewis Yap\u0131s\u0131 (Karbon Dis\u00fclf\u00fcr) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey &#8230; <a title=\"6 ad\u0131mda cs2 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/lewis-cs2-yapisi\/\" aria-label=\"More on 6 ad\u0131mda cs2 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 Ad\u0131mda CS2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/lewis-cs2-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 Ad\u0131mda CS2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CS2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki k\u00fck\u00fcrt (S) atomu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. Karbon atomu (C) ile her k\u00fck\u00fcrt atomu (S) aras\u0131nda 2 \u00e7ift ba\u011f vard\u0131r. \u0130ki k\u00fck\u00fcrt (S) atomunda 2 yaln\u0131z \u00e7ift vard\u0131r. Yukar\u0131daki CS2 Lewis Yap\u0131s\u0131 (Karbon Dis\u00fclf\u00fcr) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey ... 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