{"id":27,"date":"2023-07-26T20:20:33","date_gmt":"2023-07-26T20:20:33","guid":{"rendered":"https:\/\/chemuza.org\/tr\/2-lewisin-yapisi\/"},"modified":"2023-07-26T20:20:33","modified_gmt":"2023-07-26T20:20:33","slug":"2-lewisin-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/2-lewisin-yapisi\/","title":{"rendered":"6 ad\u0131mda of2 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-3.jpg\" alt=\"OF2 Lewis yap\u0131s\u0131\" class=\"wp-image-309\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">OF2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki flor (F) atomu ile \u00e7evrelenmi\u015f bir oksijen (O) atomu bulunur. Oksijen atomu (O) ile her flor atomu (F) aras\u0131nda 2 tekli ba\u011f vard\u0131r. Oksijen (O) atomunda 2 yaln\u0131z \u00e7ift ve iki flor (F) atomunda 3 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> OF2&#8217;nin Lewis yap\u0131s\u0131n\u0131n (oksijen diflor\u00fcr) yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, o zaman benimle kal\u0131n ve <a href=\"https:\/\/webbook.nist.gov\/cgi\/cbook.cgi?ID=C7783417&amp;Mask=1\" target=\"_blank\" rel=\"noopener\">OF2&#8217;den<\/a> Lewis&#8217;ten bir yap\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> O halde OF2&#8217;nin <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>OF2 Lewis yap\u0131s\u0131n\u0131 \u00e7izme ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: OF2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">OF2 (oksijen diflor\u00fcr) molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"http:\/\/zimmer.csufresno.edu\/~davidz\/Chem3AF97\/ChQ\/Valence.html\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle flor atomunun yan\u0131 s\u0131ra <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">oksijen<\/a> atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak florun yan\u0131 s\u0131ra oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>OF2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/8\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Flor atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4-3.jpg\" alt=\"\" class=\"wp-image-195\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Florit<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">17. grubunda yer alan<\/a> bir elementtir.<a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/9\/fluorine\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle floritte bulunan de\u011ferlik elektronu <strong>7&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"231\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5-3.jpg\" alt=\"\" class=\"wp-image-196\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi flor atomunda bulunan 7 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>OF2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 flor atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>6 + 7(2) = 20<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl OF2&#8217;dir (oksijen diflor\u00fcr) ve oksijen (O) atomlar\u0131 ve flor (F) atomlar\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda oksijen atomunun (O) ve flor atomunun (F) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Oksijenin (O) ve florun (F) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">oksijen atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada oksijen (O) atomu merkez atom, flor (F) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"60\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-1.webp\" alt=\"OF2 ad\u0131m 1\" class=\"wp-image-310\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi OF2 molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> oksijen atomu (O) ile flor atomlar\u0131 (F) aras\u0131na koymal\u0131y\u0131z. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"64\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-2.webp\" alt=\"OF2 ad\u0131m 2\" class=\"wp-image-311\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, oksijen (O) ve florinin (F) bir OF2 molek\u00fcl\u00fcnde <a href=\"https:\/\/doi.org\/10.1016\/B978-0-12-804492-6.00002-2\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f atomlar\u0131 kararl\u0131 hale getirin. Kalan de\u011ferlik elektron \u00e7iftini merkez atomun \u00fczerine yerle\u015ftirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada OF2 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n flor atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici flor atomlar\u0131 bir <a href=\"https:\/\/www.encyclopedia.com\/science\/encyclopedias-almanacs-transcripts-and-maps\/octet-rule-0\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"264\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-3.webp\" alt=\"OF2 ad\u0131m 3\" class=\"wp-image-312\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda OF2 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> OF2 molek\u00fcl\u00fcn\u00fcn toplam <strong>20 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>16 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>20 \u2013 16 = 4<\/strong> .<\/p>\n<p> Bu <strong>4<\/strong> elektronu yukar\u0131daki diyagramda OF2 molek\u00fcl\u00fcn\u00fcn merkezi oksijen atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-4.webp\" alt=\"OF2 ad\u0131m 4\" class=\"wp-image-313\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi oksijen (O) atomunun kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi oksijen (O) atomunun stabilitesini kontrol etmek i\u00e7in oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"272\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-5.webp\" alt=\"OF2 ad\u0131m 5\" class=\"wp-image-314\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde oksijen atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz. Bu, 8 elektrona sahip oldu\u011fu anlam\u0131na gelir.<\/p>\n<p> Ve b\u00f6ylece merkezi oksijen atomu stabildir.<\/p>\n<p> \u015eimdi OF2&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k OF2&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/employees.csbsju.edu\/cschaller\/Principles%20Chem\/molecules\/1_5_formal_charge.htm\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131, \u015fimdi OF2 molek\u00fcl\u00fcnde bulunan flor atomlar\u0131n\u0131n (F) yan\u0131 s\u0131ra oksijen atomlar\u0131n\u0131n (O) formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde OF2 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"356\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/de2-etape-6.webp\" alt=\"OF2 ad\u0131m 6\" class=\"wp-image-315\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Oksijen atomu (O) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4<\/p>\n<p> <strong>Florit atomu (F) i\u00e7in:<\/strong><br \/> Elektron de\u011feri = 7 (\u00e7\u00fcnk\u00fc flor 17. gruptad\u0131r)<br \/> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Ah<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> F<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 7<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan, hem <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">oksijen (O) atomunun<\/a> hem de <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">flor (F) atomunun<\/a> <strong>&#8220;s\u0131f\u0131r&#8221;<\/strong> formal y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, OF2&#8217;nin yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve OF2&#8217;nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> OF2&#8217;nin yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak OF2&#8217;nin a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-of2.jpg\" alt=\"OF2'nin Lewis yap\u0131s\u0131\" class=\"wp-image-316\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-nf3-yapisi\/\">Lewis yap\u0131s\u0131 NF3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ccl4-lewis-yapisi\/\">Lewis yap\u0131s\u0131 CCl4<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-cs2-yapisi\/\">Lewis yap\u0131s\u0131 CS2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sf6-yapisi\/\">SF6 Lewis Yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-ph3-yapisi\/\">PH3 Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-yapisi-yok\/\">HAYIR Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. OF2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki flor (F) atomu ile \u00e7evrelenmi\u015f bir oksijen (O) atomu bulunur. Oksijen atomu (O) ile her flor atomu (F) aras\u0131nda 2 tekli ba\u011f vard\u0131r. Oksijen (O) atomunda 2 yaln\u0131z \u00e7ift ve iki flor (F) atomunda 3 yaln\u0131z \u00e7ift bulunur. OF2&#8217;nin Lewis &#8230; <a title=\"6 ad\u0131mda of2 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/2-lewisin-yapisi\/\" aria-label=\"More on 6 ad\u0131mda of2 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 Ad\u0131mda OF2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/2-lewisin-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 Ad\u0131mda OF2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. OF2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki flor (F) atomu ile \u00e7evrelenmi\u015f bir oksijen (O) atomu bulunur. Oksijen atomu (O) ile her flor atomu (F) aras\u0131nda 2 tekli ba\u011f vard\u0131r. Oksijen (O) atomunda 2 yaln\u0131z \u00e7ift ve iki flor (F) atomunda 3 yaln\u0131z \u00e7ift bulunur. OF2&#8217;nin Lewis ... 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Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. OF2 Lewis yap\u0131s\u0131n\u0131n merkezinde iki flor (F) atomu ile \u00e7evrelenmi\u015f bir oksijen (O) atomu bulunur. Oksijen atomu (O) ile her flor atomu (F) aras\u0131nda 2 tekli ba\u011f vard\u0131r. Oksijen (O) atomunda 2 yaln\u0131z \u00e7ift ve iki flor (F) atomunda 3 yaln\u0131z \u00e7ift bulunur. OF2&#8217;nin Lewis ... 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