{"id":225,"date":"2023-07-25T04:54:22","date_gmt":"2023-07-25T04:54:22","guid":{"rendered":"https:\/\/chemuza.org\/tr\/yapi-clbr3-lewis\/"},"modified":"2023-07-25T04:54:22","modified_gmt":"2023-07-25T04:54:22","slug":"yapi-clbr3-lewis","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/yapi-clbr3-lewis\/","title":{"rendered":"5 ad\u0131mda clbr3 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-clbr3-lewis.jpg\" alt=\"Lewis yap\u0131s\u0131 ClBr3\" class=\"wp-image-2876\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">ClBr3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 brom (Br) atomu ile \u00e7evrelenmi\u015f bir klor (Cl) atomu bulunur. Klor atomu (Cl) ile her brom atomu (Br) aras\u0131nda 3 tekli ba\u011f vard\u0131r. Klor (Cl) atomunda 2 yaln\u0131z \u00e7ift, \u00fc\u00e7 brom (Br) atomunda ise 3 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> ClBr3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve ClBr3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> O halde ClBr3&#8217;\u00fcn <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>ClBr3 Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: ClBr3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> Bir ClBr3 <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle brom atomunun yan\u0131 s\u0131ra klor atomunda da bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size periyodik tabloyu kullanarak bromun yan\u0131 s\u0131ra klorun de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>ClBr3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Klor atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4-2.jpg\" alt=\"\" class=\"wp-image-101\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Klor periyodik tablonun 17. grubunda yer alan bir elementtir. <a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/17\/chlorine\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle klorda bulunan de\u011ferlik elektronlar\u0131 <strong>7&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"264\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5-2.jpg\" alt=\"\" class=\"wp-image-102\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi klor atomunda bulunan 7 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Brom atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-9.jpg\" alt=\"\" class=\"wp-image-653\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Brom, periyodik tablonun 17. grubunda yer alan bir elementtir. <a href=\"https:\/\/en.wikipedia.org\/wiki\/Bromine\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle bromda bulunan de\u011ferlik elektronlar\u0131 <strong>7&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"266\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-9.jpg\" alt=\"\" class=\"wp-image-654\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi brom atomunda bulunan 7 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>ClBr3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 klor atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 3 brom atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>7 + 7(3) = 28<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Tasla\u011f\u0131 haz\u0131rlay\u0131n<\/strong><\/h3>\n<p> Bir ClBr3 molek\u00fcl\u00fcn\u00fcn ana hatlar\u0131n\u0131 \u00e7izmek i\u00e7in kimyasal form\u00fcl\u00fcne bakman\u0131z yeterlidir. Merkezde bir klor (Cl) atomunun bulundu\u011funu ve bunun \u00fc\u00e7 brom (Br) atomu ile \u00e7evrelendi\u011fini g\u00f6rebilirsiniz.<\/p>\n<p> \u015eimdi bunun kaba bir tasla\u011f\u0131n\u0131 yapal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"150\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/clbr3-etape-1.webp\" alt=\"ClBr3 ad\u0131m 1\" class=\"wp-image-2877\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi ClBr3 molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> klor atomu (Cl) ile brom atomlar\u0131 (Br) aras\u0131na yerle\u015ftirmeniz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"140\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/clbr3-etape-2.webp\" alt=\"ClBr3 ad\u0131m 2\" class=\"wp-image-2878\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, klorin (Cl) ve bromin (Br), bir ClBr3 molek\u00fcl\u00fcnde birbirine <a href=\"https:\/\/www.britannica.com\/science\/chemical-bonding\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f atomlar\u0131 kararl\u0131 hale getirin. Kalan de\u011ferlik elektron \u00e7iftini merkez atomun \u00fczerine yerle\u015ftirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada ClBr3 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n brom atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici brom atomlar\u0131 bir oktet olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"386\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/clbr3-etape-3.webp\" alt=\"ClBr3 ad\u0131m 3\" class=\"wp-image-2879\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak 1. ad\u0131mda ClBr3 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektron say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> ClBr3 molek\u00fcl\u00fcnde toplam <strong>28 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>24 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>28 \u2013 24 = 4<\/strong> .<\/p>\n<p> Bu <strong>4<\/strong> elektronu yukar\u0131daki diyagramda ClBr3 molek\u00fcl\u00fcn\u00fcn merkezi klor atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"297\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/clbr3-etape-4.webp\" alt=\"ClBr3 ad\u0131m 4\" class=\"wp-image-2880\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k ClBr3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/bluebox.creighton.edu\/demo\/modules\/en-boundless-old\/www.boundless.com\/chemistry\/definition\/formal-charge\/index.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k ClBr3 molek\u00fcl\u00fcnde bulunan brom (Br) atomlar\u0131n\u0131n yan\u0131 s\u0131ra klor (Cl) atomlar\u0131n\u0131n da formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki resimde ClBr3 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"339\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/clbr3-etape-5.webp\" alt=\"ClBr3 ad\u0131m 5\" class=\"wp-image-2881\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Klor atomu (Cl) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 7 (\u00e7\u00fcnk\u00fc klor 17. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 6<br \/> Ba\u011flanmayan elektronlar = 4<\/p>\n<p> <strong>Brom atomu (Br) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 7 (\u00e7\u00fcnk\u00fc brom 17. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Cl<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 7<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> karde\u015fim<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 7<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan, hem klor (Cl) atomunun hem de bromin (Br) atomunun <strong>&#8220;s\u0131f\u0131r&#8221;<\/strong> formal y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, ClBr3&#8217;\u00fcn yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve ClBr3&#8217;\u00fcn yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> ClBr3&#8217;\u00fcn yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"https:\/\/chem.libretexts.org\/Bookshelves\/Physical_and_Theoretical_Chemistry_Textbook_Maps\/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)\/Chemical_Bonding\/Fundamentals_of_Chemical_Bonding\/Bond_Order_and_Lengths\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak ClBr3&#8217;\u00fcn a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"310\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-clbr3.jpg\" alt=\"ClBr3'\u00fcn Lewis yap\u0131s\u0131\" class=\"wp-image-2882\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-fcn-lewis\/\">Lewis FCN&#8217;nin Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/hclo2-lewis-yapisi\/\">HClO2&#8217;nin Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2cl4un-yapisi\/\">Lewis yap\u0131s\u0131 C2Cl4<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-cf3cl-yapisi\/\">Lewis Yap\u0131s\u0131 CF3Cl<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-pf3cl2nin-yapisi\/\">Lewis yap\u0131s\u0131 PF3Cl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2h4cl2nin-yapisi\/\">Lewis yap\u0131s\u0131 C2H4Cl2<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. ClBr3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 brom (Br) atomu ile \u00e7evrelenmi\u015f bir klor (Cl) atomu bulunur. Klor atomu (Cl) ile her brom atomu (Br) aras\u0131nda 3 tekli ba\u011f vard\u0131r. Klor (Cl) atomunda 2 yaln\u0131z \u00e7ift, \u00fc\u00e7 brom (Br) atomunda ise 3 yaln\u0131z \u00e7ift bulunur. ClBr3&#8217;\u00fcn Lewis &#8230; <a title=\"5 ad\u0131mda clbr3 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/yapi-clbr3-lewis\/\" aria-label=\"More on 5 ad\u0131mda clbr3 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>5 Ad\u0131mda ClBr3 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/yapi-clbr3-lewis\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"5 Ad\u0131mda ClBr3 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. ClBr3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 brom (Br) atomu ile \u00e7evrelenmi\u015f bir klor (Cl) atomu bulunur. Klor atomu (Cl) ile her brom atomu (Br) aras\u0131nda 3 tekli ba\u011f vard\u0131r. Klor (Cl) atomunda 2 yaln\u0131z \u00e7ift, \u00fc\u00e7 brom (Br) atomunda ise 3 yaln\u0131z \u00e7ift bulunur. ClBr3&#8217;\u00fcn Lewis ... 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Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. ClBr3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 brom (Br) atomu ile \u00e7evrelenmi\u015f bir klor (Cl) atomu bulunur. Klor atomu (Cl) ile her brom atomu (Br) aras\u0131nda 3 tekli ba\u011f vard\u0131r. Klor (Cl) atomunda 2 yaln\u0131z \u00e7ift, \u00fc\u00e7 brom (Br) atomunda ise 3 yaln\u0131z \u00e7ift bulunur. ClBr3&#8217;\u00fcn Lewis ... 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