{"id":21,"date":"2023-07-26T21:35:43","date_gmt":"2023-07-26T21:35:43","guid":{"rendered":"https:\/\/chemuza.org\/tr\/yapi-no3-lewis\/"},"modified":"2023-07-26T21:35:43","modified_gmt":"2023-07-26T21:35:43","slug":"yapi-no3-lewis","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/yapi-no3-lewis\/","title":{"rendered":"No3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-no3.jpg\" alt=\"NO3-Lewis yap\u0131s\u0131\" class=\"wp-image-205\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">NO3- (nitrat iyonu) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomu bulunur. Azot (N) atomu ile her oksijen (O) atomu aras\u0131nda 1 \u00e7ift ba\u011f ve 2 tek ba\u011f vard\u0131r. \u00c7ift ba\u011fl\u0131 oksijen atomunda (O) 2 yaln\u0131z \u00e7ift ve tek ba\u011fl\u0131 oksijen atomunda (O) 3 yaln\u0131z \u00e7ift vard\u0131r.<\/mark><\/em><\/strong><\/p>\n<p> NO3-Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"http:\/\/www.chemspider.com\/Chemical-Structure.918.html\" target=\"_blank\" rel=\"noopener\">NO3-<\/a> &#8216;\u00fcn Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesiyle ilgili ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi NO3-&#8216;\u00fcn <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>NO3-Lewis yap\u0131s\u0131n\u0131n \u00e7izimindeki ad\u0131mlar<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: NO3 iyonundaki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> NO3- iyonundaki (nitrat iyonu) toplam <a href=\"https:\/\/chemed.chem.purdue.edu\/genchem\/topicreview\/bp\/ch8\/#valence\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle oksijen atomunun yan\u0131 s\u0131ra nitrojen <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">atomunda<\/a> da bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak nitrojenin ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>NO3 iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-4.jpg\" alt=\"\" class=\"wp-image-84\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Azot<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">15. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/7.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 <strong>5&#8217;tir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-4.jpg\" alt=\"\" class=\"wp-image-85\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/en.wikipedia.org\/wiki\/Oxygen\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>NO3 iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 3 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 negatif y\u00fck nedeniyle eklenen ekstra 1 elektron = <strong>5 + 6(3) + 1 = 24<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen iyon NO3- iyonudur ve nitrojen (N) atomlar\u0131 ve oksijen (O) atomlar\u0131n\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda nitrojen (N) atomu ve oksijen (O) atomunun elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Azot (N) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">azot atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada nitrojen (N) atomu merkez atom, oksijen (O) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"150\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-1.webp\" alt=\"NO3-ad\u0131m 1\" class=\"wp-image-206\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi NO3 molek\u00fcl\u00fcnde <a href=\"https:\/\/www.britannica.com\/science\/electron-pair\" target=\"_blank\" rel=\"noopener\">elektron \u00e7iftlerini<\/a> nitrojen (N) atomu ile oksijen (O) atomlar\u0131 aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"152\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-2.webp\" alt=\"NO3-ad\u0131m 2\" class=\"wp-image-207\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, nitrojen (N) ve oksijenin (O) bir NO3 molek\u00fcl\u00fcnde <a href=\"https:\/\/goldbook.iupac.org\/terms\/view\/CT07009\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> NO3 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici oksijen atomlar\u0131 bir <a href=\"https:\/\/www.ck12.org\/c\/chemistry\/octet-rule\/lesson\/Octet-Rule-CHEM\/\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"304\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-3.webp\" alt=\"NO3-ad\u0131m 3\" class=\"wp-image-208\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda NO3- iyonunda bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> NO3- iyonunun toplam <strong>24 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki diyagramda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi nitrojen (N) atomunun kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi nitrojen (N) atomunun stabilitesini kontrol etmek i\u00e7in onun bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Ne yaz\u0131k ki nitrojen atomu burada bir oktet olu\u015fturmuyor. Azotun yaln\u0131zca 6 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"237\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-4.webp\" alt=\"NO3-ad\u0131m 4\" class=\"wp-image-209\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi, bu nitrojen atomunu kararl\u0131 hale getirmek i\u00e7in, d\u0131\u015ftaki oksijen atomunun elektron \u00e7iftini, nitrojen atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"161\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-5.webp\" alt=\"NO3-ad\u0131m 5\" class=\"wp-image-210\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra merkezi nitrojen atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"225\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-6.webp\" alt=\"NO3-ad\u0131m 6\" class=\"wp-image-211\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde nitrojen atomunun 8 elektrona sahip olmas\u0131 nedeniyle bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> \u015eimdi yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k NO3-&#8216;\u00fcn Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/chem.libretexts.org\/Bookshelves\/Physical_and_Theoretical_Chemistry_Textbook_Maps\/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)\/Physical_Properties_of_Matter\/Atomic_and_Molecular_Properties\/Formal_Charges\/Formal_Charge\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k NO3 molek\u00fcl\u00fcnde bulunan oksijen (O) atomlar\u0131n\u0131n yan\u0131 s\u0131ra nitrojen (N) atomlar\u0131n\u0131n da formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki resimde her NO3 iyon atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"240\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-7.webp\" alt=\"NO3-ad\u0131m 7\" class=\"wp-image-212\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Azot atomu (N) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 5 (\u00e7\u00fcnk\u00fc nitrojen 15. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>\u00c7ift ba\u011fl\u0131 oksijen (O) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4<\/p>\n<p> <strong>Tek ba\u011fl\u0131 oksijen (O) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> OLUMSUZ<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 5<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>+1<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> O (\u00e7ift atlama)<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> O (tek ba\u011f)<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> O (tek ba\u011f)<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki resmi y\u00fck hesaplamalar\u0131ndan <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">nitrojen (N) atomunun<\/a> <strong>+1<\/strong> , tek ba\u011fl\u0131 <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">oksijen (O) atomunun<\/a> ise <strong>-1<\/strong> y\u00fck\u00fcne sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> O halde bu y\u00fckleri NO3 molek\u00fcl\u00fcn\u00fcn ilgili atomlar\u0131nda tutal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"152\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-8.webp\" alt=\"NO3-ad\u0131m 8\" class=\"wp-image-213\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki diyagramdaki <strong>+1<\/strong> ve <strong>-1<\/strong> y\u00fckleri iptal edilir ve yukar\u0131daki diyagramda yaln\u0131zca <strong>-1<\/strong> y\u00fck\u00fc kal\u0131r, bu da NO3 molek\u00fcl\u00fcnde resmi <strong>-1<\/strong> y\u00fck\u00fcne neden olur.<\/p>\n<p> NO3 molek\u00fcl\u00fcndeki bu genel <strong>-1<\/strong> y\u00fck\u00fc a\u015fa\u011f\u0131daki resimde g\u00f6sterilmektedir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"176\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/no3-etape-9.webp\" alt=\"NO3-ad\u0131m 9\" class=\"wp-image-214\" srcset=\"\" sizes=\"\"><\/figure>\n<p> NO3 iyonunun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak size NO3 iyonunun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131n\u0131 verecektir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"316\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-du-no3.jpg\" alt=\"NO3-'\u00fcn Lewis yap\u0131s\u0131\" class=\"wp-image-215\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/o3-lewis-yapisi\/\">O3 Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2h2-yapisi\/\">Lewis yap\u0131s\u0131 C2H2<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch2o-lewis-yapisi\/\">CH2O Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-so3-yapisi\/\">SO3 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-c2h4-lewis\/\">Lewis yap\u0131s\u0131 C2H4<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sf4-yapisi\/\">SF4 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NO3- (nitrat iyonu) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomu bulunur. Azot (N) atomu ile her oksijen (O) atomu aras\u0131nda 1 \u00e7ift ba\u011f ve 2 tek ba\u011f vard\u0131r. \u00c7ift ba\u011fl\u0131 oksijen atomunda (O) 2 yaln\u0131z \u00e7ift ve tek ba\u011fl\u0131 &#8230; <a title=\"No3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/yapi-no3-lewis\/\" aria-label=\"More on No3- 6 ad\u0131mda lewis yap\u0131s\u0131 (resimli)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NO3- 6 ad\u0131mda Lewis yap\u0131s\u0131 (resimlerle birlikte) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/yapi-no3-lewis\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NO3- 6 ad\u0131mda Lewis yap\u0131s\u0131 (resimlerle birlikte) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NO3- (nitrat iyonu) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomu bulunur. Azot (N) atomu ile her oksijen (O) atomu aras\u0131nda 1 \u00e7ift ba\u011f ve 2 tek ba\u011f vard\u0131r. \u00c7ift ba\u011fl\u0131 oksijen atomunda (O) 2 yaln\u0131z \u00e7ift ve tek ba\u011fl\u0131 ... 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Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NO3- (nitrat iyonu) Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomu bulunur. Azot (N) atomu ile her oksijen (O) atomu aras\u0131nda 1 \u00e7ift ba\u011f ve 2 tek ba\u011f vard\u0131r. \u00c7ift ba\u011fl\u0131 oksijen atomunda (O) 2 yaln\u0131z \u00e7ift ve tek ba\u011fl\u0131 ... 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