{"id":203,"date":"2023-07-25T09:35:11","date_gmt":"2023-07-25T09:35:11","guid":{"rendered":"https:\/\/chemuza.org\/tr\/lewis-s2cl2-yapisi\/"},"modified":"2023-07-25T09:35:11","modified_gmt":"2023-07-25T09:35:11","slug":"lewis-s2cl2-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/lewis-s2cl2-yapisi\/","title":{"rendered":"6 ad\u0131mda s2cl2 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-s2cl2.jpg\" alt=\"Lewis yap\u0131s\u0131 S2Cl2\" class=\"wp-image-2627\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">Lewis yap\u0131s\u0131 S2Cl2, iki k\u00fck\u00fcrt (S) atomu aras\u0131nda ve ayr\u0131ca k\u00fck\u00fcrt (S) atomu ile klor (Cl) atomlar\u0131 aras\u0131nda tek bir ba\u011fa sahiptir. K\u00fck\u00fcrt (O) atomlar\u0131nda 2 yaln\u0131z \u00e7ift, klor (Cl) atomlar\u0131nda ise 3 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve<a href=\"https:\/\/webbook.nist.gov\/cgi\/inchi?ID=C10025679&amp;Mask=1\" target=\"_blank\" rel=\"noopener\">S2Cl2&#8217;nin<\/a> Lewis yap\u0131s\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi S2Cl2&#8217;nin <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>S2Cl2&#8217;nin Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: S2Cl2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> Bir S2Cl2 <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemed.chem.purdue.edu\/genchem\/topicreview\/bp\/ch8\/#valence\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle klor atomunun yan\u0131 s\u0131ra k\u00fck\u00fcrt atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size periyodik tabloyu kullanarak k\u00fck\u00fcrt\u00fcn ve klorun de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>S2Cl2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 K\u00fck\u00fcrt atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-3.jpg\" alt=\"\" class=\"wp-image-66\" srcset=\"\" sizes=\"\"><\/figure>\n<p> K\u00fck\u00fcrt periyodik tablonun 16. grubunda yer alan bir elementtir. <a href=\"https:\/\/education.jlab.org\/itselemental\/ele016.html\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle k\u00fck\u00fcrtteki de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"273\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-3.jpg\" alt=\"\" class=\"wp-image-67\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi k\u00fck\u00fcrt atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Klor atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4-2.jpg\" alt=\"\" class=\"wp-image-101\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Klor periyodik tablonun 17. grubunda yer alan bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/17\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle klorda bulunan de\u011ferlik elektronlar\u0131 <strong>7&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"264\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5-2.jpg\" alt=\"\" class=\"wp-image-102\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi klor atomunda bulunan 7 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>S2Cl2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 2 k\u00fck\u00fcrt atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 klor atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>6(2) + 7(2) = 26<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl S2Cl2&#8217;dir ve k\u00fck\u00fcrt (S) atomlar\u0131 ve klor (Cl) atomlar\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda k\u00fck\u00fcrt atomunun (S) ve klor atomunun (Cl) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> K\u00fck\u00fcrt (S) ve klorun (Cl) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">k\u00fck\u00fcrt atomunun elektronegatifli\u011fi daha azd\u0131r<\/a> .<\/p>\n<p> Burada k\u00fck\u00fcrt (S) atomlar\u0131 merkez atom, klor (Cl) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"50\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-1.webp\" alt=\"S2Cl2 ad\u0131m 1\" class=\"wp-image-2628\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi S2Cl2 molek\u00fcl\u00fcnde <a href=\"https:\/\/www.britannica.com\/science\/electron-pair\" target=\"_blank\" rel=\"noopener\">elektron \u00e7iftlerini<\/a> k\u00fck\u00fcrt-k\u00fck\u00fcrt atomlar\u0131 aras\u0131na ve k\u00fck\u00fcrt-klor atomlar\u0131 aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"49\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-2.webp\" alt=\"S2Cl2 ad\u0131m 2\" class=\"wp-image-2629\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bu atomlar\u0131n bir S2Cl2 molek\u00fcl\u00fcnde birbirine <a href=\"https:\/\/goldbook.iupac.org\/terms\/view\/CT07009\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f atomlar\u0131 kararl\u0131 hale getirin. Kalan de\u011ferlik elektron \u00e7iftini merkez atomun \u00fczerine yerle\u015ftirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada S2Cl2 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n klor atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici klor atomlar\u0131 bir <a href=\"https:\/\/www.ck12.org\/c\/chemistry\/octet-rule\/lesson\/Octet-Rule-CHEM\/\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"245\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-3.webp\" alt=\"S2Cl2 ad\u0131m 3\" class=\"wp-image-2630\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda S2Cl2 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> S2Cl2 molek\u00fcl\u00fcn\u00fcn toplam <strong>26 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>18 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>26 \u2013 18 = 8<\/strong> .<\/p>\n<p> Bu <strong>8<\/strong> elektronu yukar\u0131daki \u015femada S2Cl2 molek\u00fcl\u00fcn\u00fcn iki merkezi k\u00fck\u00fcrt atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"235\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-4.webp\" alt=\"S2Cl2 ad\u0131m 4\" class=\"wp-image-2631\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi k\u00fck\u00fcrt (S) atomlar\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi k\u00fck\u00fcrt (S) atomlar\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in, bunlar\u0131n bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"240\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-5.webp\" alt=\"S2Cl2 ad\u0131m 5\" class=\"wp-image-2632\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde iki k\u00fck\u00fcrt atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz. Bu, 8 elektrona sahip olduklar\u0131 anlam\u0131na gelir.<\/p>\n<p> Ve b\u00f6ylece merkezi k\u00fck\u00fcrt atomlar\u0131 kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/chem.libretexts.org\/Bookshelves\/Physical_and_Theoretical_Chemistry_Textbook_Maps\/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)\/Physical_Properties_of_Matter\/Atomic_and_Molecular_Properties\/Formal_Charges\/Formal_Charge\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131 art\u0131k S2Cl2 molek\u00fcl\u00fcnde bulunan klor (Cl) atomlar\u0131n\u0131n yan\u0131 s\u0131ra k\u00fck\u00fcrt (S) atomlar\u0131n\u0131n da formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki resimde S2Cl2 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"251\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/s2cl2-etape-6.webp\" alt=\"S2Cl2 ad\u0131m 6\" class=\"wp-image-2633\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>K\u00fck\u00fcrt (S) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc k\u00fck\u00fcrt 16. gruptad\u0131r)<br \/> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4<\/p>\n<p> <strong>Klor atomu (Cl) i\u00e7in:<\/strong><br \/> De\u011ferlik elektronlar\u0131 = 7 (\u00e7\u00fcnk\u00fc klor 17. gruptad\u0131r)<br \/> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> S<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Cl<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 7<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan k\u00fck\u00fcrt (S) atomlar\u0131n\u0131n yan\u0131 s\u0131ra klor (Cl) atomlar\u0131n\u0131n da <strong>&#8220;s\u0131f\u0131r&#8221;<\/strong> formal y\u00fcke sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, S2Cl2&#8217;nin yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve S2Cl2&#8217;nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> S2Cl2&#8217;nin yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak S2Cl2&#8217;nin a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"210\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-s2cl2.jpg\" alt=\"S2Cl2'nin Lewis yap\u0131s\u0131\" class=\"wp-image-2634\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bebr2-lewis-yapisi\/\">Lewis yap\u0131s\u0131 BeBr2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/cse2-lewis-yapisi\/\">CSe2 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/brcl-lewis-yapisi\/\">BrCl Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-ascl3-yapisi\/\">Lewis yap\u0131s\u0131 AsCl3<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2h2br2-yapisi\/\">Lewis yap\u0131s\u0131 C2H2Br2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sbcl5in-yapisi\/\">Lewis yap\u0131s\u0131 SbCl5<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 S2Cl2, iki k\u00fck\u00fcrt (S) atomu aras\u0131nda ve ayr\u0131ca k\u00fck\u00fcrt (S) atomu ile klor (Cl) atomlar\u0131 aras\u0131nda tek bir ba\u011fa sahiptir. K\u00fck\u00fcrt (O) atomlar\u0131nda 2 yaln\u0131z \u00e7ift, klor (Cl) atomlar\u0131nda ise 3 yaln\u0131z \u00e7ift bulunur. S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle &#8230; <a title=\"6 ad\u0131mda s2cl2 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/lewis-s2cl2-yapisi\/\" aria-label=\"More on 6 ad\u0131mda s2cl2 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 Ad\u0131mda S2Cl2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/lewis-s2cl2-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 Ad\u0131mda S2Cl2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 S2Cl2, iki k\u00fck\u00fcrt (S) atomu aras\u0131nda ve ayr\u0131ca k\u00fck\u00fcrt (S) atomu ile klor (Cl) atomlar\u0131 aras\u0131nda tek bir ba\u011fa sahiptir. K\u00fck\u00fcrt (O) atomlar\u0131nda 2 yaln\u0131z \u00e7ift, klor (Cl) atomlar\u0131nda ise 3 yaln\u0131z \u00e7ift bulunur. S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle ... 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Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. Lewis yap\u0131s\u0131 S2Cl2, iki k\u00fck\u00fcrt (S) atomu aras\u0131nda ve ayr\u0131ca k\u00fck\u00fcrt (S) atomu ile klor (Cl) atomlar\u0131 aras\u0131nda tek bir ba\u011fa sahiptir. K\u00fck\u00fcrt (O) atomlar\u0131nda 2 yaln\u0131z \u00e7ift, klor (Cl) atomlar\u0131nda ise 3 yaln\u0131z \u00e7ift bulunur. S2Cl2&#8217;nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle ... 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