{"id":19,"date":"2023-07-26T21:51:56","date_gmt":"2023-07-26T21:51:56","guid":{"rendered":"https:\/\/chemuza.org\/tr\/co-lewis-yapisi\/"},"modified":"2023-07-26T21:51:56","modified_gmt":"2023-07-26T21:51:56","slug":"co-lewis-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/co-lewis-yapisi\/","title":{"rendered":"5 ad\u0131mda co lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-co-lewis.jpg\" alt=\"CO Lewis'in Yap\u0131s\u0131\" class=\"wp-image-176\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">CO Lewis yap\u0131s\u0131nda bir karbon (C) atomu ve aralar\u0131nda \u00fc\u00e7l\u00fc ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Karbon (C) atomunda ve oksijen (O) atomunda 1 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> Yukar\u0131daki CO Lewis Yap\u0131s\u0131 (Karbon Monoksit) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/en.wikipedia.org\/wiki\/Carbon_monoxide\" target=\"_blank\" rel=\"noopener\">CO&#8217;nun<\/a> Lewis Yap\u0131s\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi CO&#8217;nun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>CO Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: CO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">CO (karbon monoksit) molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle oksijen atomunun yan\u0131 s\u0131ra tek bir karbon <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">atomunda<\/a> da bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">periyodik tabloyu<\/a> kullanarak karbonun ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p class=\"has-medium-font-size\"> <strong>CO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/1.jpg\" alt=\"\" class=\"wp-image-25\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Karbon<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">14. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/en.wikipedia.org\/wiki\/Carbon\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 <strong>4&#8217;t\u00fcr<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2.jpg\" alt=\"\" class=\"wp-image-26\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/8\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>CO molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>4 + 6 = 10<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> Burada verilen molek\u00fcl CO&#8217;dur (karbon monoksit). Yaln\u0131zca iki atomu vard\u0131r, dolay\u0131s\u0131yla bunlardan herhangi birini merkez atom olarak se\u00e7ebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"64\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-1.webp\" alt=\"CO ad\u0131m 1\" class=\"wp-image-177\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Karbon atomunun merkezi bir atom oldu\u011funu varsayal\u0131m.<br \/> (En az elektronegatif atomu merkez atom olarak d\u00fc\u015f\u00fcnmelisiniz).<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi CO molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> karbon atomu (C) ile oksijen atomu (O) aras\u0131na yerle\u015ftirmeniz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"63\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-2.webp\" alt=\"CO ad\u0131m 2\" class=\"wp-image-178\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bir CO molek\u00fcl\u00fcnde karbon (C) atomunun ve oksijen (O) atomunun <a href=\"https:\/\/www.britannica.com\/science\/chemical-bonding\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f atomlar\u0131 kararl\u0131 hale getirin. Kalan de\u011ferlik elektron \u00e7iftini merkez atomun \u00fczerine yerle\u015ftirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda harici atomun stabilitesini kontrol etmeniz gerekir.<\/p>\n<p> Burada CO molek\u00fcl\u00fcn\u00fcn diyagram\u0131nda karbon atomunun merkez atom oldu\u011funu varsayd\u0131k. Oksijen bu nedenle d\u0131\u015f atomdur.<\/p>\n<p> Yani oksijen atomunu kararl\u0131 hale getirmeniz gerekiyor.<\/p>\n<p> A\u015fa\u011f\u0131daki resimde oksijen atomunun bir oktet olu\u015fturdu\u011funu ve bu nedenle kararl\u0131 oldu\u011funu g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"236\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-3.webp\" alt=\"CO ad\u0131m 3\" class=\"wp-image-179\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda CO molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> CO molek\u00fcl\u00fcn\u00fcn toplam <strong>10 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>8 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>10 \u2013 8 = 2<\/strong> .<\/p>\n<p> Bu <strong>2<\/strong> elektronu yukar\u0131daki diyagramda CO molek\u00fcl\u00fcn\u00fcn karbon atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"209\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-4.webp\" alt=\"CO ad\u0131m 4\" class=\"wp-image-180\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin. Okteti yoksa yaln\u0131z \u00e7ifti \u00e7ift ba\u011f veya \u00fc\u00e7l\u00fc ba\u011f olu\u015fturacak \u015fekilde hareket ettirin.<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi karbon atomunun (C) kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Bu karbon (C) atomunun kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir.<\/p>\n<p> Maalesef bu karbon atomu burada bir oktet olu\u015fturmuyor. Karbonun yaln\u0131zca 4 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"242\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-5.webp\" alt=\"CO ad\u0131m 5\" class=\"wp-image-181\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bu karbon atomunu kararl\u0131 hale getirmek i\u00e7in elektron \u00e7iftini oksijen atomundan uzakla\u015ft\u0131rman\u0131z gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"121\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-6.webp\" alt=\"CO ad\u0131m 6\" class=\"wp-image-182\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ancak bir \u00e7ift elektronu hareket ettirdikten sonra karbon atomu yaln\u0131zca 6 elektrona sahip oldu\u011fundan hala bir oktet olu\u015fturmuyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"231\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-7.webp\" alt=\"CO ad\u0131m 7\" class=\"wp-image-183\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yine oksijen atomundan fazladan bir \u00e7ift elektronu hareket ettirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"101\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-8.webp\" alt=\"CO ad\u0131m 8\" class=\"wp-image-184\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu elektron \u00e7iftini hareket ettirdikten sonra karbon atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"255\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/co-etape-9.webp\" alt=\"CO ad\u0131m 9\" class=\"wp-image-185\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde hem karbon atomunun hem de oksijen atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Ve dolay\u0131s\u0131yla CO molek\u00fcl\u00fcn\u00fcn yukar\u0131daki Lewis nokta yap\u0131s\u0131 stabildir.<\/p>\n<p> CO&#8217;nun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"http:\/\/www.chem.ucla.edu\/~harding\/IGOC\/S\/single_bond.html\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak CO&#8217;nun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"186\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-co.jpg\" alt=\"CO'nun Lewis yap\u0131s\u0131\" class=\"wp-image-187\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/bf3-lewisin-yapisi\/\">Lewis yap\u0131s\u0131 BF3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-no3-lewis\/\">NO3-Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/o3-lewis-yapisi\/\">O3 Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2h2-yapisi\/\">Lewis yap\u0131s\u0131 C2H2<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch2o-lewis-yapisi\/\">CH2O Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-so3-yapisi\/\">SO3 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CO Lewis yap\u0131s\u0131nda bir karbon (C) atomu ve aralar\u0131nda \u00fc\u00e7l\u00fc ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Karbon (C) atomunda ve oksijen (O) atomunda 1 yaln\u0131z \u00e7ift bulunur. Yukar\u0131daki CO Lewis Yap\u0131s\u0131 (Karbon Monoksit) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve CO&#8217;nun Lewis Yap\u0131s\u0131n\u0131n nas\u0131l &#8230; <a title=\"5 ad\u0131mda co lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/co-lewis-yapisi\/\" aria-label=\"More on 5 ad\u0131mda co lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>5 Ad\u0131mda CO Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/co-lewis-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"5 Ad\u0131mda CO Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CO Lewis yap\u0131s\u0131nda bir karbon (C) atomu ve aralar\u0131nda \u00fc\u00e7l\u00fc ba\u011f i\u00e7eren bir oksijen (O) atomu bulunur. Karbon (C) atomunda ve oksijen (O) atomunda 1 yaln\u0131z \u00e7ift bulunur. Yukar\u0131daki CO Lewis Yap\u0131s\u0131 (Karbon Monoksit) g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve CO&#8217;nun Lewis Yap\u0131s\u0131n\u0131n nas\u0131l ... 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