{"id":176,"date":"2023-07-25T14:48:46","date_gmt":"2023-07-25T14:48:46","guid":{"rendered":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/"},"modified":"2023-07-25T14:48:46","modified_gmt":"2023-07-25T14:48:46","slug":"yapi-nh2oh-lewis","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/","title":{"rendered":"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-nh2oh-lewis.jpg\" alt=\"NH2OH'nin Lewis yap\u0131s\u0131\" class=\"wp-image-2333\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">NH2OH&#8217;nin Lewis yap\u0131s\u0131, merkezde iki hidrojen (H) atomu ve bir OH grubu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomuna sahiptir. \u0130ki NH ba\u011f\u0131, bir OH ba\u011f\u0131 ve bir NO ba\u011f\u0131 vard\u0131r. Azot (N) atomunda 1 yaln\u0131z \u00e7ift, oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> NH2OH&#8217;nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/webbook.nist.gov\/cgi\/cbook.cgi?ID=C7803498&amp;Mask=200\" target=\"_blank\" rel=\"noopener\">NH2OH&#8217;nin<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesiyle ilgili ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi NH2OH&#8217;nin <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>NH2OH&#8217;nin Lewis yap\u0131s\u0131n\u0131 \u00e7izme ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: NH2OH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> NH2OH <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle nitrojen atomunda, hidrojen atomunda ve oksijen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size periyodik tabloyu kullanarak nitrojen, hidrojen ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>NH2OH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-4.jpg\" alt=\"\" class=\"wp-image-84\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Azot periyodik tablonun 15. grubunda yer alan bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/7.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 <strong>5&#8217;tir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"222\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-4.jpg\" alt=\"\" class=\"wp-image-85\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Hidrojen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3.jpg\" alt=\"\" class=\"wp-image-27\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Hidrojen periyodik tablonun 1. grup elementidir. <sup>[2]<\/sup> Bu nedenle hidrojende bulunan de\u011ferlik elektronu <strong>1&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"177\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4.jpg\" alt=\"\" class=\"wp-image-28\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi hidrojen atomunda yaln\u0131zca bir de\u011ferlik elektronunun bulundu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Oksijen periyodik tablonun 16. grubunda yer alan bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/8\" target=\"_blank\" rel=\"noopener\"><sup>[3]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>NH2OH molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 3 hidrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>5 + 1(3) + 6 = 14<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> <strong>(Unutmay\u0131n:<\/strong> e\u011fer verilen molek\u00fclde hidrojen varsa, daima hidrojeni d\u0131\u015far\u0131ya koyun.)<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl NH2OH&#8217;dir ve nitrojen atomu (N), hidrojen atomlar\u0131 (H) ve oksijen atomu (O) i\u00e7erir.<\/p>\n<p> Yani kurala g\u00f6re hidrojeni d\u0131\u015far\u0131da tutmal\u0131y\u0131z. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Art\u0131k yukar\u0131daki periyodik tabloda nitrojen (N) atomu ve oksijen (O) atomunun elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Azot (N) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">azot atomu daha az elektronegatiftir<\/a> .<\/p>\n<p> Burada nitrojen (N) atomu merkez atom, oksijen (O) atomu ise d\u0131\u015f atomdur. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"114\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-1.webp\" alt=\"NH2OH ad\u0131m 1\" class=\"wp-image-2334\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi NH2OH molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> nitrojen (N), oksijen (O) ve hidrojen (H) atomlar\u0131 aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"109\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-2.webp\" alt=\"NH2OH ad\u0131m 2\" class=\"wp-image-2335\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bu atomlar\u0131n bir NH2OH molek\u00fcl\u00fcnde birbirine <a href=\"https:\/\/wou.edu\/chemistry\/courses\/online-chemistry-textbooks\/ch150-preparatory-chemistry\/ch150-chapter-4-covalent-bonds-molecular-compounds\/\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada NH2OH molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n hidrojen atomlar\u0131 ve oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu hidrojen ve oksijen atomlar\u0131 s\u0131ras\u0131yla bir <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ikili<\/a> ve bir oktet olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"281\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-3.webp\" alt=\"NH2OH ad\u0131m 3\" class=\"wp-image-2336\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda NH2OH molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> NH2OH molek\u00fcl\u00fcn\u00fcn toplam <strong>14 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>12 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>14 \u2013 12 = 2<\/strong> .<\/p>\n<p> NH2OH molek\u00fcl\u00fcn\u00fcn yukar\u0131daki diyagram\u0131nda bu <strong>2<\/strong> elektronu nitrojen atomlar\u0131n\u0131n \u00fczerine yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"242\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-4.webp\" alt=\"NH2OH ad\u0131m 4\" class=\"wp-image-2337\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi nitrojen (N) atomlar\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Merkezi nitrojen (N) atomlar\u0131n\u0131n stabilitesini kontrol etmek i\u00e7in bunlar\u0131n bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"201\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-5.webp\" alt=\"NH2OH ad\u0131m 5\" class=\"wp-image-2338\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde iki nitrojen atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Ve b\u00f6ylece bu nitrojen atomlar\u0131 kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi NH2OH&#8217;un Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k NH2OH&#8217;un Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/www.chemeurope.com\/en\/encyclopedia\/Formal_charge.html\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131saca art\u0131k NH2OH molek\u00fcl\u00fcnde bulunan nitrojen (N), hidrojen (H) ve oksijen (O) atomlar\u0131n\u0131n formal y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki g\u00f6r\u00fcnt\u00fcde NH2OH molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"323\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/nh2oh-etape-6.webp\" alt=\"NH2OH ad\u0131m 6\" class=\"wp-image-2339\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Azot atomu (N) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 5 (\u00e7\u00fcnk\u00fc nitrojen 15. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 6<br \/> Ba\u011flanmayan elektronlar = 2<\/p>\n<p> <strong>Hidrojen atomu (H) i\u00e7in:<\/strong><br \/> De\u011ferlik elektronu = 1 (\u00e7\u00fcnk\u00fc hidrojen grup 1&#8217;dedir)<br \/> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Oksijen atomu (O) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 4<br \/> Ba\u011flanmayan elektronlar = 4 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> OLUMSUZ<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 5<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> H<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 1<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Ah<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 4<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>0<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan nitrojen atomunun (N), hidrojen atomunun (H) ve oksijen atomunun (O) formal y\u00fck\u00fcn\u00fcn <strong>\u201cs\u0131f\u0131r\u201d<\/strong> oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, NH2OH&#8217;nin yukar\u0131daki Lewis yap\u0131s\u0131n\u0131n stabil oldu\u011funu ve NH2OH&#8217;nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> NH2OH&#8217;nin yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"https:\/\/en.wikipedia.org\/wiki\/Single_bond\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak, NH2OH&#8217;nin a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"243\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-nh2oh.jpg\" alt=\"NH2OH'nin Lewis yap\u0131s\u0131\" class=\"wp-image-2340\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/hclo3-lewis-yapisi\/\">Lewis Yap\u0131s\u0131 HClO3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sf5-yapisi\/\">SF5-Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-c2cl2nin-yapisi\/\">Lewis yap\u0131s\u0131 C2Cl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-n2f2-yapisi\/\">Lewis yap\u0131s\u0131 N2F2<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch2-lewis-yapisi\/\">Lewis yap\u0131s\u0131 CH2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-ho2nin-yapisi\/\">HO2-Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NH2OH&#8217;nin Lewis yap\u0131s\u0131, merkezde iki hidrojen (H) atomu ve bir OH grubu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomuna sahiptir. \u0130ki NH ba\u011f\u0131, bir OH ba\u011f\u0131 ve bir NO ba\u011f\u0131 vard\u0131r. Azot (N) atomunda 1 yaln\u0131z \u00e7ift, oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur. NH2OH&#8217;nin &#8230; <a title=\"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\" aria-label=\"More on 6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NH2OH&#8217;nin Lewis yap\u0131s\u0131, merkezde iki hidrojen (H) atomu ve bir OH grubu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomuna sahiptir. \u0130ki NH ba\u011f\u0131, bir OH ba\u011f\u0131 ve bir NO ba\u011f\u0131 vard\u0131r. Azot (N) atomunda 1 yaln\u0131z \u00e7ift, oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur. NH2OH&#8217;nin ... Devam\u0131n\u0131 oku\" \/>\n<meta property=\"og:url\" content=\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\" \/>\n<meta property=\"og:site_name\" content=\"Chemuza\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-25T14:48:46+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-nh2oh-lewis.jpg\" \/>\n<meta name=\"author\" content=\"Edit\u00f6r ekibi\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Edit\u00f6r ekibi\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\"},\"author\":{\"name\":\"Edit\u00f6r ekibi\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\"},\"headline\":\"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)\",\"datePublished\":\"2023-07-25T14:48:46+00:00\",\"dateModified\":\"2023-07-25T14:48:46+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\"},\"wordCount\":1162,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"articleSection\":[\"Lewis yap\u0131s\u0131\"],\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\",\"url\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\",\"name\":\"6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#website\"},\"datePublished\":\"2023-07-25T14:48:46+00:00\",\"dateModified\":\"2023-07-25T14:48:46+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Ev\",\"item\":\"https:\/\/chemuza.org\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/chemuza.org\/tr\/#website\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"name\":\"Chemuza\",\"description\":\"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!\",\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/chemuza.org\/tr\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"tr\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\",\"name\":\"Chemuza\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"contentUrl\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"width\":387,\"height\":70,\"caption\":\"Chemuza\"},\"image\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\",\"name\":\"Edit\u00f6r ekibi\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"caption\":\"Edit\u00f6r ekibi\"},\"sameAs\":[\"http:\/\/chemuza.org\/tr\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/","og_locale":"tr_TR","og_type":"article","og_title":"6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","og_description":"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. NH2OH&#8217;nin Lewis yap\u0131s\u0131, merkezde iki hidrojen (H) atomu ve bir OH grubu ile \u00e7evrelenmi\u015f bir nitrojen (N) atomuna sahiptir. \u0130ki NH ba\u011f\u0131, bir OH ba\u011f\u0131 ve bir NO ba\u011f\u0131 vard\u0131r. Azot (N) atomunda 1 yaln\u0131z \u00e7ift, oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur. NH2OH&#8217;nin ... Devam\u0131n\u0131 oku","og_url":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/","og_site_name":"Chemuza","article_published_time":"2023-07-25T14:48:46+00:00","og_image":[{"url":"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-nh2oh-lewis.jpg"}],"author":"Edit\u00f6r ekibi","twitter_card":"summary_large_image","twitter_misc":{"Yazan:":"Edit\u00f6r ekibi","Tahmini okuma s\u00fcresi":"6 dakika"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#article","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/"},"author":{"name":"Edit\u00f6r ekibi","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e"},"headline":"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)","datePublished":"2023-07-25T14:48:46+00:00","dateModified":"2023-07-25T14:48:46+00:00","mainEntityOfPage":{"@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/"},"wordCount":1162,"commentCount":0,"publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"articleSection":["Lewis yap\u0131s\u0131"],"inLanguage":"tr","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/","url":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/","name":"6 Ad\u0131mda NH2OH Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/#website"},"datePublished":"2023-07-25T14:48:46+00:00","dateModified":"2023-07-25T14:48:46+00:00","breadcrumb":{"@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#breadcrumb"},"inLanguage":"tr","potentialAction":[{"@type":"ReadAction","target":["https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/chemuza.org\/tr\/yapi-nh2oh-lewis\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Ev","item":"https:\/\/chemuza.org\/tr\/"},{"@type":"ListItem","position":2,"name":"6 ad\u0131mda nh2oh lewis yap\u0131s\u0131 (resimlerle)"}]},{"@type":"WebSite","@id":"https:\/\/chemuza.org\/tr\/#website","url":"https:\/\/chemuza.org\/tr\/","name":"Chemuza","description":"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!","publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/chemuza.org\/tr\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"tr"},{"@type":"Organization","@id":"https:\/\/chemuza.org\/tr\/#organization","name":"Chemuza","url":"https:\/\/chemuza.org\/tr\/","logo":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/","url":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","contentUrl":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","width":387,"height":70,"caption":"Chemuza"},"image":{"@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e","name":"Edit\u00f6r ekibi","image":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","caption":"Edit\u00f6r ekibi"},"sameAs":["http:\/\/chemuza.org\/tr"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/176"}],"collection":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/comments?post=176"}],"version-history":[{"count":0,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/176\/revisions"}],"wp:attachment":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/media?parent=176"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/categories?post=176"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/tags?post=176"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}