{"id":156,"date":"2023-07-25T18:55:18","date_gmt":"2023-07-25T18:55:18","guid":{"rendered":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/"},"modified":"2023-07-25T18:55:18","modified_gmt":"2023-07-25T18:55:18","slug":"ch3no2-lewis-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/","title":{"rendered":"6 ad\u0131mda ch3no2 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"
\"Lewis<\/figure>\n

Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n

Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n

CH3NO2 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir NO2 grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. \u00dc\u00e7 CH ba\u011f\u0131, iki NO ba\u011f\u0131 ve bir CN ba\u011f\u0131 vard\u0131r. Tekli oksijen atomlar\u0131nda 3 yaln\u0131z \u00e7ift, \u00e7ift ba\u011fl\u0131 oksijen atomunda ise 2 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n

CH3NO2’nin Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve CH3NO2’nin<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n

\u015eimdi CH3NO2’nin Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n

CH3NO2’nin Lewis yap\u0131s\u0131n\u0131 \u00e7izme ad\u0131mlar\u0131<\/strong><\/h2>\n

Ad\u0131m 1: CH3NO2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n

Bir CH3NO2 molek\u00fcl\u00fcndeki<\/a> toplam de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle karbon atomunda, hidrojen atomunda, nitrojen atomunda ve ayr\u0131ca oksijen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.
(De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n

Burada size periyodik tabloyu kullanarak karbon, hidrojen, nitrojen ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n

CH3NO2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n

\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n

\"\"<\/figure>\n

Karbon periyodik tablonun 14. grubunda yer alan bir elementtir. [1]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 4’t\u00fcr<\/strong> . <\/p>\n

\"\"<\/figure>\n

Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n

\u2192 Hidrojen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n

\"\"<\/figure>\n

Hidrojen periyodik tablonun 1. grup elementidir. [2]<\/sup><\/a> Bu nedenle hidrojende bulunan de\u011ferlik elektronu 1’dir<\/strong> . <\/p>\n

\"\"<\/figure>\n

Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi hidrojen atomunda yaln\u0131zca bir de\u011ferlik elektronunun bulundu\u011funu g\u00f6rebilirsiniz.<\/p>\n

\u2192 Azot atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n

\"\"<\/figure>\n

Azot periyodik tablonun 15. grubunda yer alan bir elementtir. [3]<\/sup><\/a> Bu nedenle nitrojende bulunan de\u011ferlik elektronlar\u0131 5’tir<\/strong> . <\/p>\n

\"\"<\/figure>\n

Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi nitrojen atomunda bulunan 5 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n

\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n

\"\"<\/figure>\n

Oksijen periyodik tablonun 16. grubunda yer alan bir elementtir. [4]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 6’d\u0131r<\/strong> . <\/p>\n

\"\"<\/figure>\n

Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n

Bu y\u00fczden,<\/p>\n

CH3NO2 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 3 hidrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 nitrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 d atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 Oksijen = 4 + 1(3) + 5 + 6 (2) = 24<\/strong> .<\/p>\n

Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n

Merkez atomu se\u00e7mek i\u00e7in en az elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n

(Unutmay\u0131n:<\/strong> e\u011fer verilen molek\u00fclde hidrojen varsa, daima hidrojeni d\u0131\u015far\u0131ya koyun.)<\/p>\n

\u015eimdi burada verilen molek\u00fcl CH3NO2’dir ve karbon atomu (C), hidrojen atomlar\u0131 (H), nitrojen atomu (N) ve oksijen atomu (O) i\u00e7erir.<\/p>\n

Yani kurala g\u00f6re hidrojeni d\u0131\u015far\u0131da tutmal\u0131y\u0131z. <\/p>\n

\"\"<\/figure>\n

Art\u0131k yukar\u0131daki periyodik tabloda karbon atomunun (C), nitrojen atomunun (N) ve oksijen atomunun (O) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n

Karbon (C), nitrojen atomu (N) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak, karbon atomu daha az elektronegatiftir<\/a> .<\/p>\n

Burada karbon (C) atomu merkez atom olup hidrojen atomlar\u0131 ve NO2 grubu onu \u00e7evreleyecektir. <\/p>\n

\"CH3NO2<\/figure>\n

Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n

\u015eimdi CH3NO2 molek\u00fcl\u00fcnde elektron \u00e7iftlerini<\/a> atomlar\u0131n aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n

\"CH3NO2<\/figure>\n

Bu, bir CH3NO2 molek\u00fcl\u00fcnde atomlar\u0131n birbirine kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n

Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n

Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n

Burada CH3NO2 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n hidrojen atomlar\u0131 ve oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n

Bu hidrojen ve oksijen atomlar\u0131 s\u0131ras\u0131yla bir ikili<\/a> ve bir oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n

\"CH3NO2<\/figure>\n

Ek olarak, 1. ad\u0131mda CH3NO2 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n

CH3NO2 molek\u00fcl\u00fcn\u00fcn toplam 24 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki CH3NO2 diyagram\u0131nda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n

Bu nedenle merkez atomlarda tutulacak elektron \u00e7ifti kalmad\u0131.<\/p>\n

\u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n

Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin<\/strong><\/h3>\n

Bu ad\u0131mda merkezi karbon atomunun (C) ve nitrojen atomunun (N) kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n

Bu atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in oktet olu\u015fturup olu\u015fturmad\u0131klar\u0131n\u0131 kontrol etmemiz gerekir. <\/p>\n

\"CH3NO2<\/figure>\n

Yukar\u0131daki resimde karbon atomunun bir oktet olu\u015fturdu\u011funu ancak nitrojenin bir oktet olu\u015fturmad\u0131\u011f\u0131n\u0131 g\u00f6rebilirsiniz. Azotun yaln\u0131zca 6 elektronu vard\u0131r ve karars\u0131zd\u0131r. <\/p>\n

\"CH3NO2<\/figure>\n

\u015eimdi, bu nitrojen atomunu kararl\u0131 hale getirmek i\u00e7in, d\u0131\u015ftaki oksijen atomunun elektron \u00e7iftini, nitrojen atomunun 8 elektrona (yani bir oktete) sahip olaca\u011f\u0131 \u015fekilde kayd\u0131rman\u0131z gerekir. <\/p>\n

\"CH3NO2<\/figure>\n

Bu elektron \u00e7iftini hareket ettirdikten sonra nitrojen atomu 2 elektron daha alacak ve b\u00f6ylece toplam elektron say\u0131s\u0131 8 olacakt\u0131r.<\/p>\n

Yukar\u0131daki resimde nitrojen atomunun 8 elektrona sahip olmas\u0131 nedeniyle bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz.<\/p>\n

Yukar\u0131daki Lewis yap\u0131s\u0131ndaki t\u00fcm atomlar\u0131n kararl\u0131 oldu\u011funu ve CH3NO2’nin yukar\u0131daki yap\u0131s\u0131nda ba\u015fka bir de\u011fi\u015fiklik olmad\u0131\u011f\u0131n\u0131 g\u00f6rebilirsiniz.<\/p>\n

CH3NO2’nin yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak CH3NO2’nin a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n

\"CH3NO2'nin<\/figure>\n

Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n

Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n

Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n

\n\n\n\n\n\n
Lewis yap\u0131s\u0131 AsH3<\/a><\/td>\n Lewis yap\u0131s\u0131 SeF6<\/a><\/td>\n<\/tr>\n
Lewis yap\u0131s\u0131 AsF3<\/a><\/td>\n Lewis yap\u0131s\u0131 KrF2<\/a><\/td>\n<\/tr>\n
Lewis yap\u0131s\u0131 SO2Cl2<\/a><\/td>\n Lewis yap\u0131s\u0131 C4H10 (B\u00fctan)<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"

Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3NO2 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir NO2 grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. \u00dc\u00e7 CH ba\u011f\u0131, iki NO ba\u011f\u0131 ve bir CN ba\u011f\u0131 vard\u0131r. Tekli oksijen atomlar\u0131nda 3 yaln\u0131z \u00e7ift, \u00e7ift ba\u011fl\u0131 oksijen atomunda ise 2 yaln\u0131z \u00e7ift bulunur. … Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"\n6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3NO2 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir NO2 grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. \u00dc\u00e7 CH ba\u011f\u0131, iki NO ba\u011f\u0131 ve bir CN ba\u011f\u0131 vard\u0131r. Tekli oksijen atomlar\u0131nda 3 yaln\u0131z \u00e7ift, \u00e7ift ba\u011fl\u0131 oksijen atomunda ise 2 yaln\u0131z \u00e7ift bulunur. ... Devam\u0131n\u0131 oku\" \/>\n<meta property=\"og:url\" content=\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\" \/>\n<meta property=\"og:site_name\" content=\"Chemuza\" \/>\n<meta property=\"article:published_time\" content=\"2023-07-25T18:55:18+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-ch3no2.jpg\" \/>\n<meta name=\"author\" content=\"Edit\u00f6r ekibi\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Edit\u00f6r ekibi\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"5 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\"},\"author\":{\"name\":\"Edit\u00f6r ekibi\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\"},\"headline\":\"6 ad\u0131mda ch3no2 lewis yap\u0131s\u0131 (resimlerle)\",\"datePublished\":\"2023-07-25T18:55:18+00:00\",\"dateModified\":\"2023-07-25T18:55:18+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\"},\"wordCount\":1037,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"articleSection\":[\"Lewis yap\u0131s\u0131\"],\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\",\"url\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\",\"name\":\"6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\",\"isPartOf\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#website\"},\"datePublished\":\"2023-07-25T18:55:18+00:00\",\"dateModified\":\"2023-07-25T18:55:18+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Ev\",\"item\":\"https:\/\/chemuza.org\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"6 ad\u0131mda ch3no2 lewis yap\u0131s\u0131 (resimlerle)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/chemuza.org\/tr\/#website\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"name\":\"Chemuza\",\"description\":\"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!\",\"publisher\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/chemuza.org\/tr\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"tr\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/chemuza.org\/tr\/#organization\",\"name\":\"Chemuza\",\"url\":\"https:\/\/chemuza.org\/tr\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"contentUrl\":\"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png\",\"width\":387,\"height\":70,\"caption\":\"Chemuza\"},\"image\":{\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e\",\"name\":\"Edit\u00f6r ekibi\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g\",\"caption\":\"Edit\u00f6r ekibi\"},\"sameAs\":[\"http:\/\/chemuza.org\/tr\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/","og_locale":"tr_TR","og_type":"article","og_title":"6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","og_description":"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3NO2 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 hidrojen (H) atomu ve bir NO2 grubu ile \u00e7evrelenmi\u015f bir karbon (C) atomu bulunur. \u00dc\u00e7 CH ba\u011f\u0131, iki NO ba\u011f\u0131 ve bir CN ba\u011f\u0131 vard\u0131r. Tekli oksijen atomlar\u0131nda 3 yaln\u0131z \u00e7ift, \u00e7ift ba\u011fl\u0131 oksijen atomunda ise 2 yaln\u0131z \u00e7ift bulunur. ... Devam\u0131n\u0131 oku","og_url":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/","og_site_name":"Chemuza","article_published_time":"2023-07-25T18:55:18+00:00","og_image":[{"url":"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-ch3no2.jpg"}],"author":"Edit\u00f6r ekibi","twitter_card":"summary_large_image","twitter_misc":{"Yazan:":"Edit\u00f6r ekibi","Tahmini okuma s\u00fcresi":"5 dakika"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#article","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/"},"author":{"name":"Edit\u00f6r ekibi","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e"},"headline":"6 ad\u0131mda ch3no2 lewis yap\u0131s\u0131 (resimlerle)","datePublished":"2023-07-25T18:55:18+00:00","dateModified":"2023-07-25T18:55:18+00:00","mainEntityOfPage":{"@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/"},"wordCount":1037,"commentCount":0,"publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"articleSection":["Lewis yap\u0131s\u0131"],"inLanguage":"tr","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/","url":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/","name":"6 Ad\u0131mda CH3NO2 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza","isPartOf":{"@id":"https:\/\/chemuza.org\/tr\/#website"},"datePublished":"2023-07-25T18:55:18+00:00","dateModified":"2023-07-25T18:55:18+00:00","breadcrumb":{"@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#breadcrumb"},"inLanguage":"tr","potentialAction":[{"@type":"ReadAction","target":["https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/chemuza.org\/tr\/ch3no2-lewis-yapisi\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Ev","item":"https:\/\/chemuza.org\/tr\/"},{"@type":"ListItem","position":2,"name":"6 ad\u0131mda ch3no2 lewis yap\u0131s\u0131 (resimlerle)"}]},{"@type":"WebSite","@id":"https:\/\/chemuza.org\/tr\/#website","url":"https:\/\/chemuza.org\/tr\/","name":"Chemuza","description":"Kimyasal ke\u015fiflere a\u00e7\u0131lan kap\u0131n\u0131z!","publisher":{"@id":"https:\/\/chemuza.org\/tr\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/chemuza.org\/tr\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"tr"},{"@type":"Organization","@id":"https:\/\/chemuza.org\/tr\/#organization","name":"Chemuza","url":"https:\/\/chemuza.org\/tr\/","logo":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/","url":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","contentUrl":"https:\/\/chemuza.org\/tr\/wp-content\/uploads\/2023\/10\/chemuza-logo.png","width":387,"height":70,"caption":"Chemuza"},"image":{"@id":"https:\/\/chemuza.org\/tr\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/5d92b9b82b9b43578b70f5a7cd51fa3e","name":"Edit\u00f6r ekibi","image":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/chemuza.org\/tr\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/0b4093cbb11daf811af20208005bf6b5?s=96&d=mm&r=g","caption":"Edit\u00f6r ekibi"},"sameAs":["http:\/\/chemuza.org\/tr"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/156"}],"collection":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/comments?post=156"}],"version-history":[{"count":0,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/posts\/156\/revisions"}],"wp:attachment":[{"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/media?parent=156"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/categories?post=156"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/chemuza.org\/tr\/wp-json\/wp\/v2\/tags?post=156"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}