{"id":130,"date":"2023-07-26T00:13:57","date_gmt":"2023-07-26T00:13:57","guid":{"rendered":"https:\/\/chemuza.org\/tr\/xeo3-lewis-yapisi\/"},"modified":"2023-07-26T00:13:57","modified_gmt":"2023-07-26T00:13:57","slug":"xeo3-lewis-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/xeo3-lewis-yapisi\/","title":{"rendered":"5 ad\u0131mda xeo3 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-xeo3-lewis.jpg\" alt=\"Lewis yap\u0131s\u0131 XeO3\" class=\"wp-image-1794\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">XeO3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir ksenon (Xe) atomu bulunur. Ksenon (Xe) ile \u00fc\u00e7 oksijen atomu (O) aras\u0131nda \u00e7ift ba\u011f vard\u0131r. Ksenon (Xe) atomunda 1 yaln\u0131z \u00e7ift, Oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n nas\u0131l \u00e7izilece\u011fine dair ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> O halde XeO3 molek\u00fcl\u00fcn\u00fcn <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>XeO3 Lewis yap\u0131s\u0131n\u0131 \u00e7izme ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: XeO3&#8217;teki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">XeO3 molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chem.libretexts.org\/Courses\/Purdue\/Purdue%3A_Chem_26505%3A_Organic_Chemistry_I_(Lipton)\/Chapter_1._Electronic_Structure_and_Chemical_Bonding\/1.03_Valence_electrons_and_open_valences\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle oksijen atomunun yan\u0131 s\u0131ra <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ksenon<\/a> atomunda da bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size periyodik tabloyu kullanarak ksenonun ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>XeO3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Ksenon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"302\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-7.jpg\" alt=\"\" class=\"wp-image-444\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ksenon periyodik tablonun 18. grubunda yer alan bir elementtir. <a href=\"https:\/\/education.jlab.org\/itselemental\/ele054.html\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle ksenonda bulunan de\u011ferlik elektronlar\u0131 <strong>8&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"284\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-7.jpg\" alt=\"\" class=\"wp-image-445\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi ksenon atomunda bulunan 8 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Oksijen periyodik tablonun 16. grubunda yer alan bir elementtir. <a href=\"https:\/\/periodic.lanl.gov\/8.shtml\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>XeO3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 1 ksenon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 3 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>8 + 6(3) = 26<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen molek\u00fcl XeO3&#8217;t\u00fcr ve ksenon (Xe) atomlar\u0131 ve oksijen (O) atomlar\u0131n\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda ksenon atomunun (Xe) ve oksijen atomunun (O) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> Ksenon (Xe) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">ksenon atomunun elektronegatifli\u011fi daha azd\u0131r<\/a> .<\/p>\n<p> Burada ksenon (Xe) atomu merkez atom, oksijen (O) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"151\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-1.webp\" alt=\"XeO3 ad\u0131m 1\" class=\"wp-image-1795\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi XeO3 molek\u00fcl\u00fcnde elektron \u00e7iftlerini ksenon atomu (Xe) ile oksijen atomlar\u0131 (O) aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"150\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-2.webp\" alt=\"XeO3 ad\u0131m 2\" class=\"wp-image-1796\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, ksenon (Xe) ve oksijenin (O) bir XeO3 molek\u00fcl\u00fcnde <a href=\"http:\/\/hyperphysics.phy-astr.gsu.edu\/hbase\/Chemical\/bond.html\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada XeO3 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici oksijen atomlar\u0131 bir oktet olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"315\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-3.webp\" alt=\"XeO3 ad\u0131m 3\" class=\"wp-image-1797\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak, 1. ad\u0131mda XeO3 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> XeO3 molek\u00fcl\u00fcnde toplam <strong>26 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>24 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>26 \u2013 24 = 2<\/strong> .<\/p>\n<p> Bu <strong>2<\/strong> elektronu yukar\u0131daki \u015femada XeO3 molek\u00fcl\u00fcn\u00fcn merkezi ksenon atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"287\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-4.webp\" alt=\"XeO3 ad\u0131m 4\" class=\"wp-image-1798\" srcset=\"\" sizes=\"\"><\/figure>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Merkezi atomdaki sekizliyi kontrol edin<\/strong><\/h3>\n<p> Bu ad\u0131mda merkezi ksenon (Xe) atomunun kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekiyor.<\/p>\n<p> Merkezi ksenon (Xe) atomunun kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in onun bir oktet olu\u015fturup olu\u015fturmad\u0131\u011f\u0131n\u0131 kontrol etmemiz gerekir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"216\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-5.webp\" alt=\"XeO3 ad\u0131m 5\" class=\"wp-image-1799\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde ksenon atomunun bir oktet olu\u015fturdu\u011funu g\u00f6rebilirsiniz. Bu, 8 elektrona sahip oldu\u011fu anlam\u0131na gelir.<\/p>\n<p> Ve b\u00f6ylece merkezi ksenon atomu kararl\u0131d\u0131r.<\/p>\n<p> \u015eimdi XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek i\u00e7in son ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 6: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k XeO3 molek\u00fcl\u00fcn\u00fcn Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"https:\/\/en.wikipedia.org\/wiki\/Formal_charge\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131, \u015fimdi XeO3 molek\u00fcl\u00fcnde bulunan oksijen atomlar\u0131n\u0131n (O) yan\u0131 s\u0131ra ksenon atomlar\u0131n\u0131n (Xe) resmi y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki resimde XeO3 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"287\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-6.webp\" alt=\"XeO3 ad\u0131m 6\" class=\"wp-image-1800\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>Ksenon atomu (Xe) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 8 (\u00e7\u00fcnk\u00fc ksenon 18. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 6<br \/> Ba\u011flanmayan elektronlar = 2<\/p>\n<p> <strong>Oksijen atomu (O) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Xe<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>+3<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Ah<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan, ksenon (Xe) atomunun <strong>+3<\/strong> , t\u00fcm oksijen atomlar\u0131n\u0131n ise <strong>-1<\/strong> y\u00fck\u00fcne sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu, XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n stabil olmad\u0131\u011f\u0131n\u0131 g\u00f6sterir.<\/p>\n<p> Bu y\u00fczden elektron \u00e7iftlerini oksijen atomlar\u0131ndan ksenon atomuna ta\u015f\u0131yarak bu y\u00fckleri en aza indirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"161\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-7.webp\" alt=\"XeO3 ad\u0131m 7\" class=\"wp-image-1801\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Elektron \u00e7iftlerini oksijen atomlar\u0131ndan ksenon atomuna ta\u015f\u0131d\u0131ktan sonra ksenon ve oksijen atomlar\u0131n\u0131n y\u00fckleri s\u0131f\u0131r olur. Ve bu daha kararl\u0131 bir Lewis yap\u0131s\u0131d\u0131r. (a\u015fa\u011f\u0131daki resme bak\u0131n). <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"159\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/xeo3-etape-8.webp\" alt=\"XeO3 ad\u0131m 8\" class=\"wp-image-1802\" srcset=\"\" sizes=\"\"><\/figure>\n<p> XeO3 molek\u00fcl\u00fcn\u00fcn yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak XeO3&#8217;\u00fcn a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"278\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-xeo3.jpg\" alt=\"XeO3'\u00fcn Lewis yap\u0131s\u0131\" class=\"wp-image-1803\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/h2co3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 H2CO3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sbr2-yapisi\/\">Lewis yap\u0131s\u0131 SBr2<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/hocl-lewis-yapisi\/\">Lewis yap\u0131s\u0131 HOCl<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/c6h6-benzen-lewis-yapisi\/\">Lewis yap\u0131s\u0131 C6H6 (Benzen)<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-nbr3-yapisi\/\">Lewis yap\u0131s\u0131 NBr3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sef4-yapisi\/\">Lewis yap\u0131s\u0131 SeF4<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. XeO3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir ksenon (Xe) atomu bulunur. Ksenon (Xe) ile \u00fc\u00e7 oksijen atomu (O) aras\u0131nda \u00e7ift ba\u011f vard\u0131r. Ksenon (Xe) atomunda 1 yaln\u0131z \u00e7ift, Oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur. XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden &#8230; <a title=\"5 ad\u0131mda xeo3 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/xeo3-lewis-yapisi\/\" aria-label=\"More on 5 ad\u0131mda xeo3 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>5 Ad\u0131mda XeO3 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/xeo3-lewis-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"5 Ad\u0131mda XeO3 Lewis Yap\u0131s\u0131 (Resimlerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. XeO3 Lewis yap\u0131s\u0131n\u0131n merkezinde \u00fc\u00e7 oksijen (O) atomu ile \u00e7evrelenmi\u015f bir ksenon (Xe) atomu bulunur. Ksenon (Xe) ile \u00fc\u00e7 oksijen atomu (O) aras\u0131nda \u00e7ift ba\u011f vard\u0131r. Ksenon (Xe) atomunda 1 yaln\u0131z \u00e7ift, Oksijen (O) atomunda ise 2 yaln\u0131z \u00e7ift bulunur. XeO3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden ... 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