{"id":125,"date":"2023-07-26T01:19:18","date_gmt":"2023-07-26T01:19:18","guid":{"rendered":"https:\/\/chemuza.org\/tr\/ch3och3-lewisin-yapisi\/"},"modified":"2023-07-26T01:19:18","modified_gmt":"2023-07-26T01:19:18","slug":"ch3och3-lewisin-yapisi","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/ch3och3-lewisin-yapisi\/","title":{"rendered":"4 ad\u0131mda ch3och3 lewis yap\u0131s\u0131 (resimlerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-ch3och3-lewis.jpg\" alt=\"Lewis yap\u0131s\u0131 CH3OCH3\" class=\"wp-image-1740\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">CH3OCH3 Lewis yap\u0131s\u0131, karbon-oksijen atomlar\u0131 aras\u0131nda ve ayr\u0131ca karbon (C) atomu ile hidrojen (H) atomu aras\u0131nda tek bir ba\u011fa sahiptir. Oksijen (O) atomunda 2 ortaklanmam\u0131\u015f \u00e7ift vard\u0131r.<\/mark><\/em><\/strong><\/p>\n<p> CH3OCH3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/compound\/Dimethyl-ether\" target=\"_blank\" rel=\"noopener\">CH3OCH3&#8217;\u00fcn<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u015eimdi CH3OCH3&#8217;\u00fcn <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>CH3OCH3 Lewis Yap\u0131s\u0131n\u0131 \u00c7izim Ad\u0131mlar\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: CH3OCH3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> Bir CH3OCH3 <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">molek\u00fcl\u00fcndeki<\/a> toplam <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">karbon atomunda<\/a> , hidrojen atomunda ve oksijen atomunda bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada size periyodik tabloyu kullanarak karbon, hidrojen ve oksijenin de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>CH3OCH3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 Karbon atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/1.jpg\" alt=\"\" class=\"wp-image-25\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Karbon periyodik tablonun 14. grubunda yer alan bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/6\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle karbonda bulunan de\u011ferlik elektronlar\u0131 <strong>4&#8217;t\u00fcr<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2.jpg\" alt=\"\" class=\"wp-image-26\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi karbon atomunda bulunan 4 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Hidrojen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3.jpg\" alt=\"\" class=\"wp-image-27\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Hidrojen periyodik tablonun 1. grup elementidir.<a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/1\/hydrogen\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle hidrojende bulunan de\u011ferlik elektronu <strong>1&#8217;dir<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"177\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/4.jpg\" alt=\"\" class=\"wp-image-28\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi hidrojen atomunda yaln\u0131zca bir de\u011ferlik elektronunun bulundu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Oksijen periyodik tablonun 16. grubunda yer alan bir elementtir. <a href=\"https:\/\/en.wikipedia.org\/wiki\/Oxygen\" target=\"_blank\" rel=\"noopener\"><sup>[3]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>CH3OCH3 molek\u00fcl\u00fcndeki toplam de\u011ferlik elektronlar\u0131<\/strong> = 2 karbon atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 6 hidrojen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 1 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 = <strong>4(2) + 1(6) + 6 = 20<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Tasla\u011f\u0131 haz\u0131rlay\u0131n<\/strong><\/h3>\n<p> CH3OCH3 molek\u00fcl\u00fcn\u00fcn bir tasla\u011f\u0131n\u0131 \u00e7izmek i\u00e7in kimyasal form\u00fcl\u00fcne bakman\u0131z yeterlidir. Merkezde bir oksijen (O) atomunun bulundu\u011funu ve her iki taraftan da CH3 ile \u00e7evrelendi\u011fini g\u00f6rebilirsiniz.<\/p>\n<p> \u015eimdi bunun kaba bir tasla\u011f\u0131n\u0131 yapal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"141\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3och3-etape-1.webp\" alt=\"CH3OCH3 ad\u0131m 1\" class=\"wp-image-1741\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi CH3OCH3 molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> karbon (C) ve oksijen (O) atomlar\u0131 aras\u0131na ve karbon (C) ve hidrojen (H) atomlar\u0131 aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"141\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3och3-etape-2.webp\" alt=\"CH3OCH3 ad\u0131m 2\" class=\"wp-image-1742\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, bu atomlar\u0131n bir CH3OCH3 molek\u00fcl\u00fcnde birbirine <a href=\"https:\/\/wou.edu\/chemistry\/courses\/online-chemistry-textbooks\/ch150-preparatory-chemistry\/ch150-chapter-4-covalent-bonds-molecular-compounds\/\" target=\"_blank\" rel=\"noopener\">kimyasal olarak ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: Kalan de\u011ferlik elektron \u00e7iftini merkez atoma yerle\u015ftirin<\/strong><\/h3>\n<p> Yukar\u0131daki CH3OCH3 tasla\u011f\u0131nda d\u0131\u015ftaki atomlar\u0131n hidrojen atomlar\u0131 oldu\u011funu ve bir ikili olu\u015fturduklar\u0131 i\u00e7in kararl\u0131 olduklar\u0131n\u0131 g\u00f6rebilirsiniz.<\/p>\n<p> \u015eimdi, 1. ad\u0131mda CH3OCH3 molek\u00fcl\u00fcnde bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> CH3OCH3 molek\u00fcl\u00fcnde toplam <strong>20 de\u011ferlik elektronu<\/strong> vard\u0131r ve yukar\u0131daki diyagramda bunlardan sadece <strong>16 de\u011ferlik elektronu<\/strong> kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Yani kalan elektron say\u0131s\u0131 = <strong>20 \u2013 16 = 4<\/strong> .<\/p>\n<p> Bu <strong>4<\/strong> elektronu yukar\u0131daki \u015femada CH3OCH3 molek\u00fcl\u00fcn\u00fcn merkezi oksijen atomuna yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"255\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/ch3och3-etape-3.webp\" alt=\"CH3OCH3 ad\u0131m 3\" class=\"wp-image-1743\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Art\u0131k yukar\u0131daki diyagramda t\u00fcm atomlar\u0131n kararl\u0131 oldu\u011funu g\u00f6rebilirsiniz (\u00e7\u00fcnk\u00fc hidrojen atomlar\u0131 <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">\u00e7iftler<\/a> olu\u015fturur ve hem karbon hem de oksijen atomlar\u0131 bir oktet olu\u015fturur.)<\/p>\n<p> Dolay\u0131s\u0131yla CH3OCH3&#8217;\u00fcn yukar\u0131daki Lewis yap\u0131s\u0131 stabildir.<\/p>\n<p> CH3OCH3&#8217;\u00fcn yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir ba\u011f elektronu \u00e7iftini (:) <a href=\"https:\/\/en.wikipedia.org\/wiki\/Single_bond\" target=\"_blank\" rel=\"noopener\">tek bir ba\u011f<\/a> (|) olarak da temsil edebilirsiniz. Bunu yapmak CH3OCH3&#8217;\u00fcn a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131na yol a\u00e7acakt\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"321\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-ch3och3.jpg\" alt=\"CH3OCH3'\u00fcn Lewis yap\u0131s\u0131\" class=\"wp-image-1744\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<p> <strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/if3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 IF3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/xeo4-lewis-yapisi\/\">Lewis yap\u0131s\u0131 XeO4<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/sf3-lewis-yapisi\/\">SF3+ Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/xeo3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 XeO3<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/h2co3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 H2CO3<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-sbr2-yapisi\/\">Lewis yap\u0131s\u0131 SBr2<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3OCH3 Lewis yap\u0131s\u0131, karbon-oksijen atomlar\u0131 aras\u0131nda ve ayr\u0131ca karbon (C) atomu ile hidrojen (H) atomu aras\u0131nda tek bir ba\u011fa sahiptir. Oksijen (O) atomunda 2 ortaklanmam\u0131\u015f \u00e7ift vard\u0131r. CH3OCH3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve CH3OCH3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m &#8230; <a title=\"4 ad\u0131mda ch3och3 lewis yap\u0131s\u0131 (resimlerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/ch3och3-lewisin-yapisi\/\" aria-label=\"More on 4 ad\u0131mda ch3och3 lewis yap\u0131s\u0131 (resimlerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>4 ad\u0131mda Lewis yap\u0131s\u0131 CH3OCH3 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/ch3och3-lewisin-yapisi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"4 ad\u0131mda Lewis yap\u0131s\u0131 CH3OCH3 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. CH3OCH3 Lewis yap\u0131s\u0131, karbon-oksijen atomlar\u0131 aras\u0131nda ve ayr\u0131ca karbon (C) atomu ile hidrojen (H) atomu aras\u0131nda tek bir ba\u011fa sahiptir. Oksijen (O) atomunda 2 ortaklanmam\u0131\u015f \u00e7ift vard\u0131r. CH3OCH3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n yukar\u0131daki g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve CH3OCH3&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ... 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