{"id":112,"date":"2023-07-26T03:42:34","date_gmt":"2023-07-26T03:42:34","guid":{"rendered":"https:\/\/chemuza.org\/tr\/lewis-so4un-yapisi-2\/"},"modified":"2023-07-26T03:42:34","modified_gmt":"2023-07-26T03:42:34","slug":"lewis-so4un-yapisi-2","status":"publish","type":"post","link":"https:\/\/chemuza.org\/tr\/lewis-so4un-yapisi-2\/","title":{"rendered":"So4 2- 5 ad\u0131mda lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)"},"content":{"rendered":"<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"650\" height=\"447\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-so42-lewis.jpg\" alt=\"SO4 2-Lewis yap\u0131s\u0131\" class=\"wp-image-1588\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi?<\/p>\n<p> Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m.<\/p>\n<p> <strong><em><mark style=\"background-color:rgba(0, 0, 0, 0);color:#ff0000\" class=\"has-inline-color\">SO4 2-Lewis yap\u0131s\u0131n\u0131n merkezinde d\u00f6rt oksijen (O) atomu ile \u00e7evrelenen bir k\u00fck\u00fcrt (S) atomu bulunur. K\u00fck\u00fcrt (S) atomu ile her Oksijen (O) atomu aras\u0131nda 2 tekli ba\u011f ve 2 \u00e7ift ba\u011f bulunmaktad\u0131r. \u00c7ift ba\u011fl\u0131 oksijen (O) atomlar\u0131nda 2 ortak \u00e7ift, tek ba\u011fl\u0131 oksijen (O) atomlar\u0131nda ise 3 ortak \u00e7ift bulunur.<\/mark><\/em><\/strong><\/p>\n<p> Yukar\u0131daki SO4 2-Lewis yap\u0131s\u0131 g\u00f6r\u00fcnt\u00fcs\u00fcnden hi\u00e7bir \u015fey anlamad\u0131ysan\u0131z, benimle kal\u0131n ve <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/compound\/Sulfate\" target=\"_blank\" rel=\"noopener\">SO4 <sup>2-<\/sup> Lewis iyonunun<\/a> Lewis yap\u0131s\u0131n\u0131n \u00e7izilmesine ili\u015fkin ayr\u0131nt\u0131l\u0131 ad\u0131m ad\u0131m a\u00e7\u0131klamay\u0131 alacaks\u0131n\u0131z.<\/p>\n<p> \u00d6yleyse SO4 <sup>2-<\/sup> iyonunun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Lewis yap\u0131s\u0131n\u0131<\/a> \u00e7izme ad\u0131mlar\u0131na ge\u00e7elim.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>SO4 \u00e7izim ad\u0131mlar\u0131 2- Lewis yap\u0131s\u0131<\/strong><\/h2>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 1: SO4 2 iyonundaki toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 bulun<\/strong><\/h3>\n<p> SO4 2- iyonundaki toplam <a href=\"https:\/\/www.lanl.gov\/orgs\/nmt\/nmtdo\/AQarchive\/04spring\/VO.html\" target=\"_blank\" rel=\"noopener\">de\u011ferlik elektron<\/a> say\u0131s\u0131n\u0131 bulmak i\u00e7in \u00f6ncelikle oksijen atomunun yan\u0131 s\u0131ra <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">k\u00fck\u00fcrt atomunda<\/a> da bulunan de\u011ferlik elektronlar\u0131n\u0131 bilmeniz gerekir.<br \/> (De\u011ferlik elektronlar\u0131 herhangi bir atomun en d\u0131\u015f <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">y\u00f6r\u00fcngesinde<\/a> bulunan elektronlard\u0131r.)<\/p>\n<p> Burada <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">size periyodik tabloyu<\/a> kullanarak oksijenin yan\u0131 s\u0131ra k\u00fck\u00fcrt\u00fcn de\u011ferlik elektronlar\u0131n\u0131 nas\u0131l kolayca bulaca\u011f\u0131n\u0131z\u0131 anlataca\u011f\u0131m.<\/p>\n<p> <strong>SO4 2 iyonundaki toplam de\u011ferlik elektronlar\u0131<\/strong><\/p>\n<p> <strong>\u2192 K\u00fck\u00fcrt atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-3.jpg\" alt=\"\" class=\"wp-image-66\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">K\u00fck\u00fcrt<\/a> periyodik tablonun <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">16. grubunda yer alan<\/a> bir elementtir. <a href=\"https:\/\/pubchem.ncbi.nlm.nih.gov\/element\/16\" target=\"_blank\" rel=\"noopener\"><sup>[1]<\/sup><\/a> Bu nedenle k\u00fck\u00fcrtteki de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"273\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-3.jpg\" alt=\"\" class=\"wp-image-67\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi k\u00fck\u00fcrt atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> <strong>\u2192 Oksijen atomunun verdi\u011fi de\u011ferlik elektronlar\u0131:<\/strong> <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"300\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/2-2.jpg\" alt=\"\" class=\"wp-image-49\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">Oksijen<\/a> periyodik tablonun 16. grubunda yer alan bir elementtir. <a href=\"https:\/\/www.rsc.org\/periodic-table\/element\/8\/oxygen\" target=\"_blank\" rel=\"noopener\"><sup>[2]<\/sup><\/a> Bu nedenle oksijende bulunan de\u011ferlik elektronlar\u0131 <strong>6&#8217;d\u0131r<\/strong> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"238\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/3-2.jpg\" alt=\"\" class=\"wp-image-50\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki resimde g\u00f6sterildi\u011fi gibi oksijen atomunda bulunan 6 de\u011ferlik elektronunu g\u00f6rebilirsiniz.<\/p>\n<p> Bu y\u00fczden,<\/p>\n<p> <strong>SO4&#8217;teki toplam de\u011ferlik elektronlar\u0131<\/strong> <strong><sup>2-<\/sup><\/strong> <strong>iyon<\/strong> = 1 k\u00fck\u00fcrt atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 4 oksijen atomu taraf\u0131ndan ba\u011f\u0131\u015flanan de\u011ferlik elektronlar\u0131 + 2 ekstra elektron, 2 negatif y\u00fck nedeniyle eklenir = <strong>6 + 6(4) + 2 = 32<\/strong> .<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 2: Merkez atomu se\u00e7in<\/strong><\/h3>\n<p> Merkez atomu se\u00e7mek i\u00e7in en az <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektronegatif<\/a> atomun merkezde kald\u0131\u011f\u0131n\u0131 unutmamal\u0131y\u0131z.<\/p>\n<p> \u015eimdi burada verilen iyon SO4 2- iyonudur ve k\u00fck\u00fcrt (S) atomlar\u0131 ve oksijen (O) atomlar\u0131n\u0131 i\u00e7erir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"800\" height=\"478\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/5.jpg\" alt=\"\" class=\"wp-image-29\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki periyodik tabloda k\u00fck\u00fcrt atomunun (S) ve oksijen atomunun (O) elektronegatiflik de\u011ferlerini g\u00f6rebilirsiniz.<\/p>\n<p> K\u00fck\u00fcrt (S) ve oksijenin (O) elektronegatiflik de\u011ferlerini kar\u015f\u0131la\u015ft\u0131r\u0131rsak <a href=\"https:\/\/chemuza.org\/tr\/periyodik-tablonun-elektronegatifligi\/\">k\u00fck\u00fcrt atomunun elektronegatifli\u011fi daha azd\u0131r<\/a> .<\/p>\n<p> Burada k\u00fck\u00fcrt (S) atomu merkez atom, oksijen (O) atomlar\u0131 ise d\u0131\u015f atomlard\u0131r. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"231\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-1.webp\" alt=\"SO42-ad\u0131m 1\" class=\"wp-image-1589\" srcset=\"\" sizes=\"\"><\/figure>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 3: Her atomu aralar\u0131na bir \u00e7ift elektron yerle\u015ftirerek ba\u011flay\u0131n<\/strong><\/h3>\n<p> \u015eimdi SO4 molek\u00fcl\u00fcnde <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">elektron \u00e7iftlerini<\/a> k\u00fck\u00fcrt atomu (S) ile oksijen atomlar\u0131 (O) aras\u0131na yerle\u015ftirmeniz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"226\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-2.webp\" alt=\"SO42-ad\u0131m 2\" class=\"wp-image-1590\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Bu, k\u00fck\u00fcrt (S) ve oksijenin (O) bir SO4 molek\u00fcl\u00fcnde <a href=\"https:\/\/whs.rocklinusd.org\/documents\/Science\/2011_Reading_the_Different_Types_of_Bonds.pdf\" target=\"_blank\" rel=\"noopener\">kimyasal olarak birbirine ba\u011fland\u0131\u011f\u0131n\u0131<\/a> g\u00f6sterir.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 4: D\u0131\u015f Atomlar\u0131 Kararl\u0131 Hale Getirin<\/strong><\/h3>\n<p> Bu ad\u0131mda d\u0131\u015f atomlar\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol etmeniz gerekir.<\/p>\n<p> Burada SO4 molek\u00fcl\u00fcn\u00fcn \u00e7iziminde d\u0131\u015ftaki atomlar\u0131n oksijen atomlar\u0131 oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> Bu harici oksijen atomlar\u0131 bir <a href=\"https:\/\/openpress.usask.ca\/intro-organic-chemistry\/chapter\/1-2\/\" target=\"_blank\" rel=\"noopener\">oktet<\/a> olu\u015fturur ve bu nedenle stabildir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"387\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-3.webp\" alt=\"SO42-ad\u0131m 3\" class=\"wp-image-1591\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Ek olarak 1. ad\u0131mda SO4 <sup>2-<\/sup> iyonunda bulunan toplam de\u011ferlik elektronu say\u0131s\u0131n\u0131 hesaplad\u0131k.<\/p>\n<p> SO4 <sup>2-<\/sup> iyonunun toplam <strong>32 de\u011ferlik elektronu<\/strong> vard\u0131r ve bu de\u011ferlik elektronlar\u0131n\u0131n t\u00fcm\u00fc yukar\u0131daki diyagramda kullan\u0131lm\u0131\u015ft\u0131r.<\/p>\n<p> Bu nedenle merkez atomda tutulacak daha fazla elektron \u00e7ifti yoktur.<\/p>\n<p> \u015eimdi bir sonraki ad\u0131ma ge\u00e7elim.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Ad\u0131m 5: Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131n\u0131 kontrol edin<\/strong><\/h3>\n<p> Art\u0131k SO4 <sup>2-<\/sup> iyonunun Lewis yap\u0131s\u0131n\u0131n stabilitesini kontrol etmeniz gereken son ad\u0131ma geldiniz.<\/p>\n<p> Lewis yap\u0131s\u0131n\u0131n kararl\u0131l\u0131\u011f\u0131 <a href=\"http:\/\/home.miracosta.edu\/dlr\/info\/formal_charge.htm\" target=\"_blank\" rel=\"noopener\">formal y\u00fck<\/a> kavram\u0131 kullan\u0131larak do\u011frulanabilir.<\/p>\n<p> K\u0131sacas\u0131, \u015fimdi SO4 molek\u00fcl\u00fcnde bulunan oksijen atomlar\u0131n\u0131n (O) yan\u0131 s\u0131ra k\u00fck\u00fcrt atomlar\u0131n\u0131n (S) resmi y\u00fck\u00fcn\u00fc bulmam\u0131z gerekiyor.<\/p>\n<p> Resmi vergiyi hesaplamak i\u00e7in a\u015fa\u011f\u0131daki form\u00fcl\u00fc kullanman\u0131z gerekir:<\/p>\n<p class=\"has-background\" style=\"background-color:#ffe9cf\"> <strong>Resmi y\u00fck = De\u011ferlik elektronlar\u0131 \u2013 (Ba\u011f elektronlar\u0131)\/2 \u2013 Ba\u011f yapmayan elektronlar<\/strong><\/p>\n<p> A\u015fa\u011f\u0131daki resimde SO4 molek\u00fcl\u00fcn\u00fcn her bir atomu i\u00e7in <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanan elektronlar\u0131n<\/a> ve <a href=\"https:\/\/chemuza.org\/tr\/kimyanin-temel-tanimlari\/\">ba\u011flanmayan elektronlar\u0131n<\/a> say\u0131s\u0131n\u0131 g\u00f6rebilirsiniz. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"311\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-4.webp\" alt=\"SO42-ad\u0131m 4\" class=\"wp-image-1592\" srcset=\"\" sizes=\"\"><\/figure>\n<p> <strong>K\u00fck\u00fcrt (S) atomu i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc k\u00fck\u00fcrt 16. gruptad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 8<br \/> Ba\u011flanmayan elektronlar = 0<\/p>\n<p> <strong>Oksijen atomu (O) i\u00e7in:<\/strong><strong><br \/><\/strong> De\u011ferlik elektronlar\u0131 = 6 (\u00e7\u00fcnk\u00fc oksijen grup 16&#8217;dad\u0131r)<strong><br \/><\/strong> Ba\u011f elektronlar\u0131 = 2<br \/> Ba\u011flanmayan elektronlar = 6 <\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Resmi su\u00e7lama<\/strong><\/td>\n<td> <strong>=<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>de\u011ferlik elektronlar\u0131<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>(Elektronlar\u0131n ba\u011flanmas\u0131)\/2<\/strong><\/td>\n<td> <strong>\u2013<\/strong><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>Ba\u011flanmayan elektronlar<\/strong> <\/td>\n<td><\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> S<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 8\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>+2<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"has-text-align-center\" data-align=\"center\"> Ah<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 2\/2<\/td>\n<td> \u2013<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 6<\/td>\n<td> =<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> <strong>-1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Yukar\u0131daki formal y\u00fck hesaplamalar\u0131ndan k\u00fck\u00fcrt (S) atomunun <strong>+2<\/strong> , t\u00fcm oksijen atomlar\u0131n\u0131n ise <strong>-1<\/strong> y\u00fck\u00fcne sahip oldu\u011funu g\u00f6rebilirsiniz.<\/p>\n<p> O halde bu y\u00fckleri SO4 molek\u00fcl\u00fcn\u00fcn ilgili atomlar\u0131nda tutal\u0131m. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"228\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-5.webp\" alt=\"SO42-ad\u0131m 5\" class=\"wp-image-1593\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Yukar\u0131daki g\u00f6r\u00fcnt\u00fc SO4&#8217;\u00fcn Lewis yap\u0131s\u0131n\u0131n kararl\u0131 olmad\u0131\u011f\u0131n\u0131 g\u00f6stermektedir.<\/p>\n<p> Bu y\u00fczden elektron \u00e7iftini oksijen atomundan k\u00fck\u00fcrt atomuna ta\u015f\u0131yarak bu y\u00fckleri en aza indirmemiz gerekiyor. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"230\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-6.webp\" alt=\"SO42-ad\u0131m 6\" class=\"wp-image-1594\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Elektron \u00e7iftini oksijen atomundan k\u00fck\u00fcrt atomuna ta\u015f\u0131d\u0131ktan sonra k\u00fck\u00fcrt ve iki oksijen atomunun y\u00fckleri s\u0131f\u0131r olur. Ve bu daha kararl\u0131 bir Lewis yap\u0131s\u0131d\u0131r. (a\u015fa\u011f\u0131daki resme bak\u0131n). <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"228\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-7.webp\" alt=\"SO42-ad\u0131m 7\" class=\"wp-image-1595\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Oksijen atomlar\u0131nda iki <strong>-ve<\/strong> y\u00fck\u00fc kal\u0131r ve SO4 molek\u00fcl\u00fcne resmi <strong>-2<\/strong> y\u00fck\u00fc verir.<\/p>\n<p> SO4 molek\u00fcl\u00fcndeki bu genel <strong>-2<\/strong> y\u00fck\u00fc a\u015fa\u011f\u0131daki resimde g\u00f6sterilmektedir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"207\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/so42-etape-8.webp\" alt=\"SO42-ad\u0131m 8\" class=\"wp-image-1596\" srcset=\"\" sizes=\"\"><\/figure>\n<p> SO4 2-iyonunun yukar\u0131daki Lewis nokta yap\u0131s\u0131nda, her bir <a href=\"https:\/\/mccord.cm.utexas.edu\/chembook\/page.php?chnum=4&amp;sect=5\" target=\"_blank\" rel=\"noopener\">ba\u011f elektronu \u00e7iftini<\/a> (:) tek bir ba\u011f (|) olarak da temsil edebilirsiniz. Bunu yapmak size SO4 2-iyonunun a\u015fa\u011f\u0131daki Lewis yap\u0131s\u0131n\u0131 verecektir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full\"><img decoding=\"async\" loading=\"lazy\" width=\"600\" height=\"389\" src=\"https:\/\/chemuza.org\/wp-content\/uploads\/2023\/08\/structure-de-Lewis-de-so42.jpg\" alt=\"SO42-'nin Lewis yap\u0131s\u0131\" class=\"wp-image-1597\" srcset=\"\" sizes=\"\"><\/figure>\n<p> Umar\u0131m yukar\u0131daki t\u00fcm ad\u0131mlar\u0131 tamamen anlam\u0131\u015fs\u0131n\u0131zd\u0131r.<\/p>\n<p> Daha fazla pratik yapmak ve daha iyi anlamak i\u00e7in a\u015fa\u011f\u0131da listelenen di\u011fer Lewis yap\u0131lar\u0131n\u0131 deneyebilirsiniz.<\/p>\n<style>\n.wp-block-table table, .wp-block-table td, .wp-block-table th {\n    border: 0;\n}\n<\/style>\n<p><strong>Daha iyi anlamak i\u00e7in \u015fu Lewis yap\u0131lar\u0131n\u0131 deneyin (veya en az\u0131ndan g\u00f6r\u00fcn):<\/strong><\/p>\n<figure class=\"wp-block-table\">\n<table>\n<tbody>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-2nin-clo2-yapisi\/\">ClO2&#8217;nin Lewis yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/lewis-br2-yapisi\/\">Lewis yap\u0131s\u0131 Br2<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/yapi-becl2-lewis\/\">Lewis yap\u0131s\u0131 BeCl2<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/ch3coo-lewis-yapisi\/\">CH3COO \u2013 Lewis yap\u0131s\u0131<\/a><\/td>\n<\/tr>\n<tr>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/aseton-c3h6o-lewis-yapisi\/\">Aseton (C3H6O) Lewis Yap\u0131s\u0131<\/a><\/td>\n<td> <a href=\"https:\/\/chemuza.org\/tr\/pocl3-lewis-yapisi\/\">Lewis yap\u0131s\u0131 POCl3<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. SO4 2-Lewis yap\u0131s\u0131n\u0131n merkezinde d\u00f6rt oksijen (O) atomu ile \u00e7evrelenen bir k\u00fck\u00fcrt (S) atomu bulunur. K\u00fck\u00fcrt (S) atomu ile her Oksijen (O) atomu aras\u0131nda 2 tekli ba\u011f ve 2 \u00e7ift ba\u011f bulunmaktad\u0131r. \u00c7ift ba\u011fl\u0131 oksijen (O) atomlar\u0131nda 2 ortak \u00e7ift, tek ba\u011fl\u0131 oksijen (O) atomlar\u0131nda &#8230; <a title=\"So4 2- 5 ad\u0131mda lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/tr\/lewis-so4un-yapisi-2\/\" aria-label=\"More on So4 2- 5 ad\u0131mda lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle)\">Devam\u0131n\u0131 oku<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>SO4 2- 5 ad\u0131mda Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/chemuza.org\/tr\/lewis-so4un-yapisi-2\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"SO4 2- 5 ad\u0131mda Lewis yap\u0131s\u0131 (g\u00f6r\u00fcnt\u00fclerle) - Chemuza\" \/>\n<meta property=\"og:description\" content=\"Yukar\u0131daki g\u00f6rseli zaten g\u00f6rd\u00fcn\u00fcz de\u011fil mi? Yukar\u0131daki g\u00f6rseli k\u0131saca a\u00e7\u0131klayay\u0131m. SO4 2-Lewis yap\u0131s\u0131n\u0131n merkezinde d\u00f6rt oksijen (O) atomu ile \u00e7evrelenen bir k\u00fck\u00fcrt (S) atomu bulunur. K\u00fck\u00fcrt (S) atomu ile her Oksijen (O) atomu aras\u0131nda 2 tekli ba\u011f ve 2 \u00e7ift ba\u011f bulunmaktad\u0131r. \u00c7ift ba\u011fl\u0131 oksijen (O) atomlar\u0131nda 2 ortak \u00e7ift, tek ba\u011fl\u0131 oksijen (O) atomlar\u0131nda ... 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