{"id":946,"date":"2023-07-20T02:12:34","date_gmt":"2023-07-20T02:12:34","guid":{"rendered":"https:\/\/chemuza.org\/pt\/esta-fervendo-endotermico-ou-exotermico\/"},"modified":"2023-07-20T02:12:34","modified_gmt":"2023-07-20T02:12:34","slug":"esta-fervendo-endotermico-ou-exotermico","status":"publish","type":"post","link":"https:\/\/chemuza.org\/pt\/esta-fervendo-endotermico-ou-exotermico\/","title":{"rendered":"A ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica? (e porque?)"},"content":{"rendered":"<p><strong>A ebuli\u00e7\u00e3o \u00e9 um <a href=\"https:\/\/www.khanacademy.org\/test-prep\/mcat\/chemical-processes\/thermochemistry\/a\/endothermic-vs-exothermic-reactions\" target=\"_blank\" rel=\"noopener\">processo endot\u00e9rmico<\/a> . A energia t\u00e9rmica \u00e9 necess\u00e1ria para transformar um l\u00edquido em um g\u00e1s. Durante a ebuli\u00e7\u00e3o, as mol\u00e9culas l\u00edquidas ganham energia, superam as for\u00e7as intermoleculares e passam para a fase gasosa, absorvendo assim o calor do ambiente.<\/strong><\/p>\n<p> Bem, essa foi apenas uma resposta simples. Mas h\u00e1 mais algumas coisas que voc\u00ea deve saber sobre esse assunto que deixar\u00e3o seu conceito muito claro.<\/p>\n<p> Ent\u00e3o, vamos direto ao assunto. <\/p>\n<div class=\"inherit-container-width wp-block-group key is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group__inner-container\">\n<h3 class=\"wp-block-heading\"> <strong>Principais conclus\u00f5es: a ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica?<\/strong><\/h3>\n<ul>\n<li> A ebuli\u00e7\u00e3o \u00e9 um processo endot\u00e9rmico porque requer uma entrada de energia t\u00e9rmica para transformar um l\u00edquido em g\u00e1s.<\/li>\n<li> A fervura envolve a absor\u00e7\u00e3o de energia do meio ambiente, o que a distingue dos processos exot\u00e9rmicos que liberam energia.<\/li>\n<li> A energia t\u00e9rmica fornecida durante a ebuli\u00e7\u00e3o \u00e9 usada para quebrar as for\u00e7as intermoleculares e fazer a transi\u00e7\u00e3o das mol\u00e9culas l\u00edquidas para a fase gasosa.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<h2 class=\"wp-block-heading\"> <strong>Porque \u00e9 que a fervura \u00e9 um processo endot\u00e9rmico?<\/strong><\/h2>\n<p class=\"ans\"> <em>A ebuli\u00e7\u00e3o \u00e9 um processo endot\u00e9rmico porque requer uma entrada de energia para superar as for\u00e7as intermoleculares entre as mol\u00e9culas l\u00edquidas. Quando um l\u00edquido \u00e9 aquecido at\u00e9 ao ponto de ebuli\u00e7\u00e3o, a energia adicionada quebra as liga\u00e7\u00f5es que mant\u00eam as mol\u00e9culas unidas, permitindo-lhes escapar para a fase gasosa.<\/em><\/p>\n<p> Num l\u00edquido, as mol\u00e9culas est\u00e3o em movimento constante e s\u00e3o atra\u00eddas umas pelas outras por for\u00e7as intermoleculares, como liga\u00e7\u00f5es de hidrog\u00e9nio ou <a href=\"https:\/\/en.wikipedia.org\/wiki\/London_dispersion_force\" target=\"_blank\" rel=\"noopener\">for\u00e7as de dispers\u00e3o de Londres<\/a> . Essas for\u00e7as criam um efeito coesivo, mantendo as mol\u00e9culas l\u00edquidas pr\u00f3ximas umas das outras.<\/p>\n<p> Quando o calor \u00e9 aplicado ao l\u00edquido, sua temperatura aumenta e a energia cin\u00e9tica m\u00e9dia das mol\u00e9culas tamb\u00e9m aumenta. No entanto, as for\u00e7as intermoleculares devem ser superadas para passar da fase l\u00edquida para a fase gasosa.<\/p>\n<p> Durante a ebuli\u00e7\u00e3o, a energia t\u00e9rmica fornecida \u00e9 usada para quebrar essas for\u00e7as intermoleculares, em vez de aumentar a temperatura do l\u00edquido.<\/p>\n<p> \u00c0 medida que as mol\u00e9culas l\u00edquidas ganham energia suficiente, elas superam as for\u00e7as de atra\u00e7\u00e3o e passam para a fase gasosa. Essa absor\u00e7\u00e3o de energia do meio ambiente, na forma de calor, torna a ebuli\u00e7\u00e3o um processo endot\u00e9rmico.<\/p>\n<p> Em resumo, a ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica porque requer uma entrada de energia para superar as for\u00e7as intermoleculares e mover as mol\u00e9culas l\u00edquidas para a fase gasosa.<\/p>\n<h2 class=\"wp-block-heading\"> <strong>Porque \u00e9 que a fervura n\u00e3o \u00e9 um processo exot\u00e9rmico?<\/strong><\/h2>\n<p class=\"ans\"> <em>A fervura n\u00e3o \u00e9 um <a href=\"https:\/\/en.wikipedia.org\/wiki\/Exothermic_process\" target=\"_blank\" rel=\"noopener\">processo exot\u00e9rmico<\/a> porque envolve a absor\u00e7\u00e3o de energia do meio ambiente e n\u00e3o a libera\u00e7\u00e3o de energia. Quando um l\u00edquido atinge o ponto de ebuli\u00e7\u00e3o, \u00e9 necess\u00e1rio calor para quebrar as for\u00e7as intermoleculares e facilitar a transi\u00e7\u00e3o das mol\u00e9culas da fase l\u00edquida para a fase gasosa.<\/em><\/p>\n<p> Os processos exot\u00e9rmicos envolvem a libera\u00e7\u00e3o de energia, geralmente na forma de calor, para o meio ambiente. Por exemplo, quando uma subst\u00e2ncia sofre <a href=\"https:\/\/www.grc.nasa.gov\/www\/k-12\/airplane\/combst1.html\" target=\"_blank\" rel=\"noopener\">combust\u00e3o<\/a> , ela libera energia t\u00e9rmica.<\/p>\n<p> Por\u00e9m, no caso da fervura, a energia do meio ambiente \u00e9 absorvida. Essa energia \u00e9 utilizada para superar as for\u00e7as de atra\u00e7\u00e3o entre as mol\u00e9culas l\u00edquidas, permitindo-lhes escapar para a fase gasosa.<\/p>\n<p> Quando o calor \u00e9 aplicado a um l\u00edquido, aumenta a energia cin\u00e9tica das mol\u00e9culas. \u00c0 medida que a temperatura aumenta, as mol\u00e9culas se movem com mais vigor e sua velocidade m\u00e9dia aumenta.<\/p>\n<p> No entanto, a energia adicionada \u00e9 usada principalmente para superar as for\u00e7as intermoleculares, em vez de ser liberada como calor. Esta absor\u00e7\u00e3o de energia do ambiente torna a ebuli\u00e7\u00e3o um processo endot\u00e9rmico, o que a distingue dos processos exot\u00e9rmicos.<\/p>\n<h3 class=\"wp-block-heading\"> <strong>Leitura adicional<\/strong><\/h3>\n<p> <a href=\"https:\/\/chemuza.org\/pt\/a-fotossintese-e-endotermica-ou-exotermica\/\">A fotoss\u00edntese \u00e9 endot\u00e9rmica ou exot\u00e9rmica?<br \/><\/a> <a href=\"https:\/\/chemuza.org\/pt\/a-combustao-e-endotermica-ou-exotermica\/\">A combust\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica?<br \/><\/a> <a href=\"https:\/\/chemuza.org\/pt\/e-o-derretimento-endotermico-ou-exotermico-do-gelo\/\">O derretimento do gelo \u00e9 endot\u00e9rmico ou exot\u00e9rmico?<br \/><\/a> <a href=\"https:\/\/chemuza.org\/pt\/e-sublimacao-endotermica-ou-exotermica\/\">A sublima\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica?<\/a><br \/> <a href=\"https:\/\/chemuza.org\/pt\/e-fusao-endotermica-ou-exotermica-e-por-que\/\">O ferro fundido \u00e9 endot\u00e9rmico ou exot\u00e9rmico?<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>A ebuli\u00e7\u00e3o \u00e9 um processo endot\u00e9rmico . A energia t\u00e9rmica \u00e9 necess\u00e1ria para transformar um l\u00edquido em um g\u00e1s. Durante a ebuli\u00e7\u00e3o, as mol\u00e9culas l\u00edquidas ganham energia, superam as for\u00e7as intermoleculares e passam para a fase gasosa, absorvendo assim o calor do ambiente. Bem, essa foi apenas uma resposta simples. Mas h\u00e1 mais algumas coisas &#8230; <a title=\"A ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica? (e porque?)\" class=\"read-more\" href=\"https:\/\/chemuza.org\/pt\/esta-fervendo-endotermico-ou-exotermico\/\" aria-label=\"Mais em A ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica? (e porque?)\">Ler mais<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[12],"tags":[],"class_list":["post-946","post","type-post","status-publish","format-standard","hentry","category-estrutura-de-lewis"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A ebuli\u00e7\u00e3o \u00e9 endot\u00e9rmica ou exot\u00e9rmica? 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